Question

For each sequence,find the first 4 terms and the 10th term a) n+5 b)2n-1

Answer 1

Answer:

a)6,7,8,9 and 10th term is 15.

b)1,3,5,7 and 10th term is 19.

Step-by-step explanation:

Given a) n+5

b)2n-1

Solution for  a) n+5

Taking the value of n is 1 we get the first term of the sequence;

$n+5=1+5=6$

Similarly taking the value of n 2,3,4 we get;

$2+5=7\\3+5=8\\4+5=9$

And for 10th term we take the value of n is 10 and get;

$n+5=10+5=15$

So the solution for 1st sequence is 6,7,8,9 and 10th term is 15.

Solution for  b)2n-1

Taking the value of n is 1 we get the first term of the sequence;

$2n-1=2\times1-1=2-1=1$

Similarly taking the value of n 2,3,4 we get;

$2n-1=2\times2-1=4-1=3\\2\times3-1=6-1=5\\2\times4-1=8-1=7$

And for 10th term we take the value of n is 10 and get;

$2n-1=2\times10-1=20-1=19$

So the solution for 2nd sequence is 1,3,5,7 and 10th term is 19.