To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
Answer:
It should be the first quadrant
Hope that helps!
Answer:
15. C
16. A
Step-by-step explanation:
Good luck brotha!
7,500 x 2 = 15,000
you know you can just use a calculator...
Answer:
6
Step-by-step explanation:
30/5 =6 and yeah That's alll