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Mathematics

1 answer:

nydimaria [60]3 years ago

7 0

Answer:

Step-by-step explanation:

vertex of g(x) is (0, 0), so:

$g(x)=a(x-0)^2+0\\\\g(x)=ax^2 \qquad and\qquad (2,\,1)\in g(x)\\\\1=a\cdot2^2\\1=4a\\a=\frac14\\\\g(x)=\frac14x^2=(\frac12x)^2$

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Answer:

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Step-by-step explanation:

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Leya [2.2K]

Answer:

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Step-by-step explanation:

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