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Tcecarenko [31]
3 years ago
10

Factorise the following 5y^2-20y-8z+2yz

Mathematics
1 answer:
andre [41]3 years ago
8 0

Answer:

(5y+2z)(y-4)

Step-by-step explanation:

5y^2-20y-8z+2yz=\\5y^2-20y+2yz-8z=\\5y(y-4)+2z(y-4)=\\(5y+2z)(y-4)

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Just need help here pls
julia-pushkina [17]

Answer:

k=6, k=-1

Step-by-step explanation:

                         \dfrac{k+3}{3}-\dfrac{2}{k-5}=1

\implies \dfrac{(k+3)(k-5)}{3(k-5)}-\dfrac{3 \cdot 2}{3(k-5)}=1

\implies \dfrac{k^2-2k-15-6}{3(k-5)}=1

\implies k^2-2k-21=3k-15

\implies k^2-5k-6=0

\implies (k-6)(k+1)=0

\implies k=6, k=-1

7 0
2 years ago
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erik [133]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
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ddd [48]

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3 years ago
F(x)=2x+6
Klio2033 [76]

Answer:

Step-by-step explanation:

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6 0
3 years ago
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What is the value of one divided by zero?
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Step-by-step explanation:

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