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IrinaVladis [17]
3 years ago
6

If the probability that your DVD player breaks down before the extended warranty expires is 0.034, what is the probability that

the player will not break down before the warranty expires
Mathematics
1 answer:
schepotkina [342]3 years ago
7 0

Answer:

0.966

Step-by-step explanation:

Given that:

Probability of DVD player breaking down before the warranty expires = 0.034

To find:

The probability that the player will not break down before the warranty expires = ?

Solution:

Here, The two events are:

1. The DVD player breaks down before the warranty gets expired.

2. The DVD player breaks down after the warranty gets expired

In other words, the 2nd event can be stated as:

The DVD does not break down before the warranty gets expired.

The two events here, have nothing in common i.e. they are mutually exclusive events.

So, Sum of their probabilities will be equal to 1.

\bold{P(E_1)+P(E_2)=1}\\\Rightarrow 0.034+P(E_2)=1\\\Rightarrow P(E_2)=1-0.034\\\Rightarrow P(E_2)=\bold{0.966}

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Use synthetic division to find P (-10) for P(x)=2x^3+14x^2-58x
Savatey [412]
The polynomial remainder theorem states that the remainder upon dividing a polynomial p(x) by x-c is the same as the value of p(c), so to find p(-10) you need to find the remainder upon dividing

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--------------------------
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kap26 [50]

Answer:

<h2><em><u>0.6 = 6/10 = 3/5 is the answer.</u></em></h2>

Step-by-step explanation:

0.6 = 6/10 = 3/5

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This is because you have to substitute.

Given:

x = 3

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Unknown:

Final Answer

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