Question

A) The sixth term of an AP is twice the 3rd term and the first term is 3. Find the common

Answer 1

Answer:

Step-by-step explanation:

The nth term of an AP is expressed as;

Tn = a+(n-1)d

a is the first term

n is the number of terms

d is the common difference

Sixth term

T6 = a+(6-1)d

T6 = a+5d

Third term;

T3 = a+(3-1)d

T3 = a+2d

If the sixth term of an AP is twice the 3rd term, then

a+5d = 2(a+2d)

a+5d = 2a+4d

Given a = 3

3+5d = 2(3)+4d

5d-4d = 6-3

d = 3

Common difference is 3

For the 10th term

T10 = a+9d

T10 = 3+9(3)

T10 = 3+27

T10 = 30

Hence the tenth term is 30