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vlabodo [156]
3 years ago
6

Did you mean to put -31 or did you mean to put equal 31

Mathematics
1 answer:
babymother [125]3 years ago
4 0
-31 is a thing and it would be pronounced negative thirty-one hope that helps
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1. (k+7)² =289<br>2. (2s-1)² =225<br>3. (x-4)² =169<br><br>please help me answer these :)
professor190 [17]
(k+7)^2 =289\\&#10;|k+7|=17\\&#10;k+7=17\vee k+7=-17\\&#10;k=10 \vee k=-24

(2s-1)^2 =225\\&#10;|2s-1|=15\\&#10;2s-1=15\vee 2s-1=-15\\&#10;2s=16 \vee 2s=-14\\&#10;s=8 \vee s=-7

(x-4)^2 =169\\&#10;|x-4|=13\\&#10;x-4=13 \vee x-4=-13\\&#10;x=17 \vee x=-9
6 0
4 years ago
Read 2 more answers
PLEASE HELP NO ONE WILL PLEASE
kakasveta [241]
Right cylinderSolve for volumeV≈1005.31cm³<span><span><span>rRadiuscm</span><span>hHeightcm</span></span></span>
6 0
3 years ago
Ratiearbiteracy
ipn [44]
Explanation

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5 0
3 years ago
X over -5 =15 <br> whats the solution to this equation
skad [1K]

Answer:

<em>x = -75</em>

Step-by-step explanation:

\frac{x}{-5} = 15

15 * -5 = -75

x = -75

Hope this helps! :)

8 0
3 years ago
Read 2 more answers
Point T is on line segment S U ‾ SU . Given T U = x − 1 , TU=x−1, S U = 3 x − 7 , SU=3x−7, and S T = x + 7 , ST=x+7, determine t
dangina [55]

Answer:

TU = 12

Step-by-step explanation:

Given

TU = x − 1

SU = 3x − 7

ST = x + 7

TU = ?

Then we can say that

SU = ST + TU

⇒  3x − 7 = (x + 7) + (x − 1)

⇒  3x − 7 = 2x + 6

⇒  x = 13

Finally, we get

TU = x − 1

⇒  TU = 13 - 1

⇒  TU = 12

Therefore,

ST = x + 7 = 13 + 7 = 20

SU = 3x − 7 = 3*(13) - 7 = 32

6 0
3 years ago
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