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AURORKA [14]
3 years ago
9

2 (y - 5x) - 7y + 9x

Mathematics
2 answers:
pogonyaev3 years ago
7 0
Simplify the expression: -x-5y
liubo4ka [24]3 years ago
4 0
-x-5y I simplified it you should use apps like Socratic and photomath it’s better
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Write Y=4/3x-4 in slope intercept form
sergij07 [2.7K]

Answer:

Y=4/3x-4

Step-by-step explanation:

You have it in slope intercept form =)

7 0
3 years ago
Find the quotient. 2 1/3 ÷ 1 <br><br> help
Jet001 [13]

Answer:

2 \frac{1}{3}  \div 1 \frac{1}{3}  \\ = \frac{7}{3}  \div  \frac{4}{3}  \\ = \frac{7}{3}  \times  \frac{3}{4}  \\  =  \frac{7}{4}

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4 0
3 years ago
A textbook store sold a combined total of 289 sociology and math textbooks in a week. The number of math textbooks sold was 65 l
erica [24]

Answer:

Contradictrion

Step-by-step explanation:

First write an equation. If the total is 289, then that goes one the right side of the =. Sociology textbooks will be x. If there were 65 less than x, it will be 65-x. Lets set it up:

x + 65 -x =289

Then combine like terms.

65 = 289

There are no values of x that make the equation true. The input is a contradiction.

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8 0
3 years ago
X +5+11x=12x+Y It says find the value of y that makes each equation true for all values of
sladkih [1.3K]
X + 5 + 11x = 12x + y

Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)

Subtract 12x from each side makes each zero.

5 = y

So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82

x = 10, y = 5
10 + 5 + 11(10) = 12(10) + 5
125 = 125

x = 82, y = 5
82 + 5 + 11(82) = 12(82) + 5
989 = 989

So we verified y = 5
3 0
3 years ago
Drag the tiles to list the sides of △MNO from shortest to longest.
sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

  • MO/Shortest MO/Medium and MO/Longest

a) <u>Friday</u>

b) <u>70 minutes</u>

c) <u>40%</u>

d) Yes<u>,</u> <u>the sum of the </u><u>mean</u><u> number of </u><u>minutes spent</u><u> on </u><u>aerobic</u><u> training and the mean number of minutes spent on </u><u>strength</u><u> training is equal to the mean </u><u>total</u><u> number of minutes spent </u><u>training.</u>

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= \frac{}{MO}

The next shortest side is the side opposite ∠M(61°) = \frac{}{NO}

The longest side is the side opposite ∠O(65°) = \frac{}{MN}

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on <u>Friday</u>

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = <u>70 minutes</u>

<u />

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

The  percentage spent on strength training = \frac{120}{300} × 100 = \frac{40}%

d) The mean number of minutes spent on strength training is found as follows;

Mean_{strength} =\frac{120}{5} =24

The mean number of minutes spent on aerobic training is found as follows;

Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36

Mean_{strength} +Mean_{aerobic} =24+36=60

The mean total number of minutes spent training, Mean_{total} = \frac{300}{5} = 60

Therefore;

  • Mean_{strength}+Mean_{aerobic} = Mean_{total} \\

Learn more here:

brainly.com/question/2962546

4 0
3 years ago
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