Answer:
x = 10
y = 3
Step-by-step explanation:
Given
2x - 6y = 2
x + 6y = 28
Add both equations
2x + x -6y + 6y = 2 + 28
3x = 30
Divide both sides by 3
x = 30/3
x = 10
Substitute 10 for x in either equations to get y
Using equation 2 , we have
x + 6y = 28
10 + 6y = 28
Subtract 10 from both sides
10 - 10 + 6y = 28 - 10
6y = 18
Divide both sides by by 6
y = 18/6
y = 3
Therefore
x = 10
y = 3
0.4 because if it’s five or more, add one more. If it’s four or less, let it rest.
4x - 2 > 6
4x > 8
x > 2
x + 3 <= -6
x <= -9
so answer in interval notation is (-∞, -9] or (2, ∞)
Remember the order of operations. The first step in this problem will be to solve the exponent.
Take (2x)^3. Remember that since there are parentheses around 2x, that means you have to cube 2 and x.
(2x)^3 = 2^3 * x^3 = 8x^3
Now multiply that answer by 4 to finish simplifying.
8x^3 * 4 = 32 x^3
Your answer should be: 32x^3
31 is g = -19
32 is x = -9
34 is w = -11
31:
g-(-7) = -12
g+7 = -12
g = -19
32:
-5x = 45 divide by -5
x = -9
33 looks like it has a print error so I can’t figure that out, I don’t know where the |-2| is supposed to be
34:
(w-1)/4 = -3 multiply by 4
w - 1 = -12
w = -11
