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almond37 [142]
3 years ago
13

Solve the following problem. PV=$24,122; n = 70; i = 0.024; PMT ?; PMT = $ (Round to two decimal places.)

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

Answer:

The payment per period is $714.82.

Step-by-step explanation:

Given information: PV=$24,122; n = 70; i = 0.024

The formula for payment per period is

PMT=\frac{PV\times i}{1-(1+i)^{-n}}

Substitute PV=$24,122; n = 70; i = 0.024 in the above formula.

PMT=\frac{24122\times 0.024}{1-(1+0.024)^{-70}}

PMT=\frac{578.928}{0.80989084337}

PMT=714.822256282

PMT\approx 714.82

Therefore the payment per period is $714.82.

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dexar [7]
Given f(x,\ y)=x^2-y^2-2 subject to the constraint x^2+y^2=16

Let g(x,\ y)=x^2+y^2.

The gradient vectors of f and g are:

\nabla f(x,\ y)=\langle2x,-2y\rangle and \nabla g(x,\ y)=\langle2x,2y\rangle

By Lagrange's theorem, there is a number \lambda, such that

\langle2x,-2y\rangle=\lambda\langle2x,2y\rangle=\langle2\lambda x,2\lambda y\rangle

\lambda=\pm1

It can be seen that f(x,\ y)=x^2-y^2-2 has local extreme values at the given region.
6 0
3 years ago
S/4-6.8=-9.8 what does s equal
Hatshy [7]
S/4-6.8=-9.8
S/4= -9.8+6.8
S/4= -3
S=-3*4
S= -12
4 0
3 years ago
What are the zeros of f(x)=x^2+x-20?
zzz [600]
F(x) = x² + x - 20 = x² + 5x - 4x - 20 = x(x + 5) - 4(x + 5) = (x + 5)(x - 4)

f(x) = 0 ⇔ (x + 5)(x - 4) = 0 ⇔ x + 5 = 0 or x - 4 = 0 ⇒ x = -5 or x = 4

Answer: C. x = -5 and x = 4.
3 0
3 years ago
Factor 70q+60. Write your answer as a product with a whole number greater than 1.
faltersainse [42]

Answer:

10(7q + 6)

Step-by-step explanation:

  1. Find the GCF of 70 and 60: 10
  2. Divide each number by 10 (steps shown below)
  3. 70q ÷ 10 = 7q
  4. 60 ÷ 10 = 6
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I hope this helps!

7 0
3 years ago
Please help .god bless you
zhenek [66]

Answer:Area of the lawn is 1725 ft^2

Step-by-step explanation:

The yard is in the shape of a trapezoid. The area of the lawn can be determined by finding the area of the trapezoid. The formula for determining the area of a trapezoid is expressed as

Area of trapezoid =

1/2(a + b)h

Where

a is the length of one of the parallel sides of the trapezoid

b is the length of the other parallel side of the trapezoid.

h is the perpendicular height of the the trapezoid.

From the diagram,

a = 50 feet

b = 65 feet

h = 30 feet

Area of the lawn = 1/2(50 + 65)× 30

= 1/2 × 115 × 30 = 1725 ft^2

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3 years ago
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