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velikii [3]
3 years ago
12

Is the correct or this wrong, pleaee let me know if its wrong and explain

Mathematics
2 answers:
Natalija [7]3 years ago
6 0
Wrong. its clearly wrong like how can you think that is right.
Reptile [31]3 years ago
4 0
Your y-int. is correct but your slope is wrong . you go up 2 to the right 1 time then repeat
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What is 1500 biweekly
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$1500 income every 2 weeks, I think.

Step-by-step explanation:

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Pls PLS solve T_T i tried everything ​
Rudik [331]

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12√3 is the correct answer

6 0
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Read 2 more answers
<img src="https://tex.z-dn.net/?f=5x%20%20%2B%2011%287x%20-%203" id="TexFormula1" title="5x + 11(7x - 3" alt="5x + 11(7x - 3"
Murljashka [212]

82x - 33 ✅

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}

5x + 11(7x - 3) \\  = 5x + 77x - 33 \\  = 82x - 33

\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}

3 0
2 years ago
What is the largest integer n such that (n^2-38) / (n +1) is an integer?
Phantasy [73]

Answer:

a. 36

Step-by-step explanation:

for (n^2-38)/(n+1) to be an integer, n+1 must completely divide, n^2-38.

we check with the options

option a n=36 sutisfies the above condition.

(36^2-38)/36+1 = 1258/37= 34 , which is an integer. Therefore, largest integer would be 36

6 0
3 years ago
Why does cube root 7 equal 7 to the 1/3 power
UNO [17]

Answer:

Step-by-step explanation:

Here's how you convert:

\sqrt[n]{x^m}=x^{\frac{m}{n}  The little number outside the radical, called the index, serves as the denominator in the rational power, and the power on the x inside the radical serves as the numerator in the rational power on the x.

A couple of examples:

\sqrt[3]{x^4}=x^{\frac{4}{3}

\sqrt[5]{x^7}=x^{\frac{7}{5}

It's that simple. For your problem in particular:

\sqrt[3]{7} is the exact same thing as \sqrt[3]{7^1}=7^{\frac{1}{3}

8 0
3 years ago
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