Hello.
Taking a look at our screenshot provided, we can conclude that we need to find the missing angle degree out of 90 degrees, as we are dealing with a right angle.
Let's set this up as an Algebraic formula and solve for the variable;
5x + 15 + 50 = 90
First, let's combine like-terms (15 and 50).
5x + 65 = 90
Now, isolate our variable by subtracting 65 from each side of the equation.
90 - 65 = 25
65 - 65 = 0
5x = 25
Now, divide both sides by 5 to solve for x, our missing angle degree.
x = 5
Your answer is A.) 5
I hope this helps!
C. -4,-5 hope this helps :)
The required plane Π contains the line
L: (-1,1,2)+t(7,6,2)
means that Π is perpendicular to the direction vector of the line L, namely
vl=<7,6,2>
It is also required that Π be perpendicular to the plane
Π 1 : 5y-7z+8=0
means that Π is also perpendicular to the normal vector of the given plane, vp=<0,5,-7>.
Thus the normal vector of the required plane, Π can be obtained by the cross product of vl and vp, or vl x vp:
i j k
7 6 2
0 5 -7
=<-42-10, 0+49, 35-0>
=<-52, 49, 35>
which is the normal vector of Π
Since Π has to contain the line, it must pass through the point (-1,1,2), so the equation of the plane is
Π : -52(x-(-1))+49(y-1)+35(z-2)=0
=>
Π : -52x+49y+35z = 171
Check that normal vector of plane is orthogonal to line direction vector
<-52,49,35>.<7,6,2>
=-364+294+70
=0 ok
