Answer: It's either -6 or 12. I'm assuming it's 12 because it says "more than."
Step-by-step explanation:
Answer:

Step-by-step explanation:
a = 3, b = 5, c = 1
plug into quadratic formula
8/9+(-5/6)= 8/9-5/6 = 1/18
Therefore, 1/18/(1/6)
1/18*1/6 (cancel out)
your answer is 1/3
Given that

, then

The slope of a tangent line in the polar coordinate is given by:

Thus, we have:

Part A:
For horizontal tangent lines, m = 0.
Thus, we have:

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:
</span><span>θ = 0
</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488
Part B:
For vertical tangent lines,

Thus, we have:

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:
</span>θ = <span>4.91718592528713</span>
<span>a. direct variation
A relationship between two variables in which one is a constant multiple of the other. </span>