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Serggg [28]
3 years ago
13

CAN SOMEONE HELP ME WITH THIS????????????????

Mathematics
1 answer:
Lerok [7]3 years ago
4 0

\text{Hello there!}\\\\\text{We're trying to find the area of the shape}\\\text{We can do this by finding the area for the different shapes, then adding}\\\text{them together}\\\\\text{We can find the area of the rectangle,} \,\,84\cdot66=5,544\\\\\text{To find the area of the half circle, we would use the equation:}\,\,A=\frac{3.14r^2}{2}\\\\\text{The radius is half of the diameter, therefore it is 33. Plug 33 in r}\\\\A=\frac{3.14(33)^2}{2}\\\\\text{Solve:}\\\\A=\frac{3.14(33)^2}{2}\\

A=\frac{3.14(1089)}{2}\\\\A=\frac{3419.46}{2}\\\\\text{Divide by 2}\\\\A=1709.73\\\\\text{Since there's two half circles, we would add 1709.73 twice}\\\\\text{Add all the areas together}\\\\1709.73+1709.73+5,544=8963.46\\\\\large\boxed{\text{Area:}\,\,8963.46\,\,\text{m}^2}}

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This is Pythagorean's Theorem, with one leg being 10 and the hypotenuse being 16.  Using those values in the theorem looks like this:
10^{2} + b^{2} = 16^{2}
and 100+ b^{2} =256
and b^{2} =256-100
so b^{2} =156
Take the square root of both sides to find that b = 12.5
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3 years ago
(0,4), (1,0), (2,0), (2,3), (3,1) is it a function
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Vas happenin!!

A proper function is when the x value is NOT repeating


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-Zayn Malik
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2 years ago
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5 0
3 years ago
Read 2 more answers
4(2y-7)=64+12y<br> 2y-7=16+3y<br> 5y=23<br> Y=4.6<br> Is this equivalent? <br> (Explain)
ratelena [41]
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8 0
3 years ago
A spherical balloon was inflated such that it had a diameter of 24 centimeters. Additional helium was then added to the balloon
DanielleElmas [232]
To solve this we are going to use the formula for the volume of a sphere: V= \frac{4}{3}  \pi r^3
where 
r is the radius of the sphere 

Remember that the radius of a sphere is half its diameter; since the first radius of our sphere is 24 cm, r= \frac{24}{2} =12. Lets replace that in our formula: 
V= \frac{4}{3} \pi r^3
V= \frac{4}{3} \pi (12)^3
V=7238.23 cm^3

Now, the second diameter of our sphere is 36, so its radius will be: r= \frac{36}{2} =18. Lets replace that value in our formula one more time:
V= \frac{4}{3} \pi r^3
V= \frac{4}{3} \pi (18)^3
V=24429.02

To find the volume of the additional helium, we are going to subtract the volumes:
Volume of helium=24429.02cm^3-7238.23cm^3=17190.79cm^3

We can conclude that the volume of additional helium in the balloon is approximately <span>17,194 cm³.</span>
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3 years ago
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