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Serggg [28]
3 years ago
13

CAN SOMEONE HELP ME WITH THIS????????????????

Mathematics
1 answer:
Lerok [7]3 years ago
4 0

\text{Hello there!}\\\\\text{We're trying to find the area of the shape}\\\text{We can do this by finding the area for the different shapes, then adding}\\\text{them together}\\\\\text{We can find the area of the rectangle,} \,\,84\cdot66=5,544\\\\\text{To find the area of the half circle, we would use the equation:}\,\,A=\frac{3.14r^2}{2}\\\\\text{The radius is half of the diameter, therefore it is 33. Plug 33 in r}\\\\A=\frac{3.14(33)^2}{2}\\\\\text{Solve:}\\\\A=\frac{3.14(33)^2}{2}\\

A=\frac{3.14(1089)}{2}\\\\A=\frac{3419.46}{2}\\\\\text{Divide by 2}\\\\A=1709.73\\\\\text{Since there's two half circles, we would add 1709.73 twice}\\\\\text{Add all the areas together}\\\\1709.73+1709.73+5,544=8963.46\\\\\large\boxed{\text{Area:}\,\,8963.46\,\,\text{m}^2}}

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I think you are referring to this:
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3 years ago
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Oksana_A [137]

Answer:

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  2. see below
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Step-by-step explanation:

Applying the squaring rule to each of the elements of the domain, we get ...

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1. There are 7 different numbers in the Domain list.

2. See above

3. There are 5 different numbers in the Range list.

4. The rule "square me" is not "one-to-one" Two different values in the domain can result in the same value in the range. -3 and 3 both result in 9. -1/2 and 0.5 both result in 1/4.

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3 years ago
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Serjik [45]
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3 0
3 years ago
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