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3 years ago

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Riley is making a trip 100 miles to visit his friend Steve. After traveling for 2 hours at 45 miles per hour, Riley realizes tha

t he made a wrong turn. He turns around and drives 20 miles in 40 minutes. Then, Riley stops to read the map for ten minutes. He continues on the correct route at 30 miles per hour until he arrives at Steve's house.

1 answer:

andrezito [222]3 years ago

4 0

Have you ever been snaked by a friend ‍then ‍♀️just for ‍ the clout❕they’lldo it again .

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Find the value of x.

frozen [14]

Answer:

x + 42 + 58 = 180
x + 100 = 180
x = 80°

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3 years ago

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How can you find the area of a triangle using the Law of Sines?

aniked [119]

Explanation:

One formula for the area of a triangle is ...

Area = (1/2)ab·sin(C)

This presumes you know the measures of two sides and the angle between them. The Law of Sines is typically used where you know all the angles and only one side measure.

You would use the law of sines to find an additional side measure, then make use of the above formula for area.

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2 years ago

Philip walked a total of 8 kilometers by making 2 trips to school. After 3 trips to school, how many kilometers will Philip have

vekshin1

So one trip = 4 km
two trips = 8
8 + 4 = 12
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3 years ago

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The computer that controls a bank's automatic teller machine crashes a mean of 0.6 times per day. What is the probability that,

professor190 [17]

Answer:

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Mean of 0.6 times a day

7 day week, so $\mu = 7*0.6 = 4.2$

What is the probability that, in any seven-day week, the computer will crash less than 3 times? Round your answer to four decimal places.

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-4.2}*(4.2)^{0}}{(0)!} = 0.0150$

$P(X = 1) = \frac{e^{-4.2}*(4.2)^{1}}{(1)!} = 0.0630$

$P(X = 2) = \frac{e^{-4.2}*(4.2)^{2}}{(2)!} = 0.1323$

So

$P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0150 + 0.0630 + 0.1323 = 0.2103$

0.2103 = 21.03% probability that, in any seven-day week, the computer will crash less than 3 times.

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2 years ago

PLEASE HELP!!!!!!!!!!!!

katovenus [111]

Let me ask my brother he's smart

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2 years ago