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sashaice [31]
2 years ago
5

On the bottom #4 the choices are •trapezoid •isosceles triangle •scalene triangle

Mathematics
2 answers:
KIM [24]2 years ago
5 0
The answers is an Isosceles triangle
pentagon [3]2 years ago
5 0
Yep, the answer is isosceles triangle.
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Use the parabola tool to graph the quadratic function. f(x)=2x2+12x+16
yKpoI14uk [10]
We have that
<span>f(x)=2x</span>²<span>+12x+16

using a graph tool
see the attached figure</span>

7 0
3 years ago
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Find the center of a circle with the equation: x2 y2−32x−60y 1122=0 x 2 y 2 − 32 x − 60 y 1122 = 0
mixas84 [53]

The equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

The center of the circle exists at (16, 30).

<h3>What is the equation of a circle?</h3>

Let, the equation of a circle exists:

$(x-h)^2 + (y-k)^2 = r^2, where (h, k) be the center.

We rewrite the equation and set them equal :

$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0

$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

To learn more about center of the circle refer to:

brainly.com/question/10633821

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7 0
1 year ago
Thomas needs to buy a cardboard sheet that will allow him to make his 224 in 3 box. To help construct the box, he decided to cut
Slav-nsk [51]

Answer:

Part 1; The volume of the box Thomas wants to make is 224 = 2·w² + 12·w

Part 2; The zeros for the equation of the function, are w = -14, or w = 8

Part 3

The width of the box is 8 inch

The length of the box, is 14 inches

The height of the box, is given as 2 inches

Part 4

Please find attached the graph of the function

Step-by-step explanation:

Part 1

The volume of the box Thomas wants to make, V = 224 in.³

The dimensions he cuts out from the length and width = 2 in² each

The length of the box = 6 inches + The width of the box

Let <em>l</em> represent the length of the box and let <em>w</em> represent the width of the box, we have;

l = 6 + w

The height of the box, h = The length of the cut out square = 2 inches

The volume of the box, V = Length, l × Width, w × Height, h

∴ V = l × w × h

l = 6 + w, h = 2

∴ V = (6 + w) × w × 2

V = 2·w² + 12·w,

The equation of the volume of the box, V = 2·w² + 12·w, where, V = 224

∴ 224 = 2·w² + 12·w

Part 2

The zeros of the equation for the volume of the box, V = 2·w² + 12·w, where, V = 224 are found as follows;

V = 224 = 2·w² + 12·w

∴ 2·w² + 12·w - 224 = 0

Dividing by 2 gives;

(2·w² + 12·w - 224)/2 = w² + 6·w - 112 = 0

∴ (w + 14) × (w - 8) = 0

The zeros for the equation of the function, are w = -14, or w = 8

Part 3

We reject the value, w = -14, therefore, the width of the box, w = 8 inch

The length of the box, l = 6 + w

∴ l = 6 + 8 = 14

The length of the box, l = 8 inches

The height of the box, <em>h</em>, is given as h = 2 inches

Part 4

The graph of the function created with MS Excel is attached

4 0
3 years ago
Solve the inequality for u.<br> 22≤-4u-2<br> Simplify your answer as much as possible.
larisa [96]

Answer:

<u>u ≤ -6</u>

Step-by-step explanation:

Given :

  • 22 ≤ -4u - 2

Add 2 on both sides :

  • 22 + 2 ≤ -4u - 2  + 2
  • -4u ≥ 24

Divide both sides by -4 (remember the sign changes direction when divided by a negative number) :

  • -4u/-4 ≥ 24/-4
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7 0
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Amit solved the equation StartFraction 5 over 12 EndFraction = Negative StartFraction x over 420 EndFraction for x using the ste
melomori [17]

Answer:

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-AKA-

The product of StartFraction 5 over 12 EndFraction and –420 should have been the value of x.

-AKA-

The product of 5/12 and –420 should have been the value of x.

Step-by-step explanation:

i did it on edge 2020

see..........

hope it helps        :)

7 0
3 years ago
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