A) Interest = principal * rate * time
I = (800)(0.05)(3) = $120
b) $800 + $120 = $920 after the three years. $920 * (1 - 0.02) = $901.60.
The rule of distributive property allows you to rewrite xa + xb as x (a + b).
So if x = 2, a = 3 and b = 4, xa + xb = x(a + b)
(2 * 3) + (2 * 4) = 2 (3 + 4)
6 + 8 = 14
14 = 14
...and so on. You may try it yourself with different variations.
Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.
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To find the probability of landing on a triangle, you will want find the combined areas of the triangles and the total area of the square target.
Divide the area of the combined areas and the total area to find the probability of landing on a triangle.
A = 1/2bh
1/2 x 8 x 8
A = 32 square inches
32 x 4
128 square inches (areas of triangles)
A = bh
26 x 26
A = 676 square inches
128/676 = 0.189
There is an approximate probability of 0.19 of hitting a triangle.
Answer:
I think k = 2 and m = 19
and I also think in order to mention the steps there must be another clue or equation
![\bf \begin{array}{llll} &[(-6,2),(2,3),(1,1),(-7,2),(4,2)]\\\\ inverse& [(2,-6),(3,2),(1,1),(2,-7),(2,4)] \end{array} \\\\\\ \textit{is the original a one-to-one?}\qquad \stackrel{rep eated~y-values}{(-6,\stackrel{\downarrow }{2}),(2,3),(1,1),(-7,\stackrel{\downarrow }{2}),(4,\stackrel{\downarrow }{2})}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0A%26%5B%28-6%2C2%29%2C%282%2C3%29%2C%281%2C1%29%2C%28-7%2C2%29%2C%284%2C2%29%5D%5C%5C%5C%5C%0Ainverse%26%20%5B%282%2C-6%29%2C%283%2C2%29%2C%281%2C1%29%2C%282%2C-7%29%2C%282%2C4%29%5D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bis%20the%20original%20a%20one-to-one%3F%7D%5Cqquad%20%5Cstackrel%7Brep%20eated~y-values%7D%7B%28-6%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%2C%282%2C3%29%2C%281%2C1%29%2C%28-7%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%2C%284%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%7D)
notice, the inverse set is just, the same set with the x,y turned to y,x, backwards.
is it a one-to-one? well, for a set to be a one-to-one, it must not have any x-repeats, that is, the value of the first in the pairs must not repeat, and it also must not have any y-repeats, namely the value of the second in the pairs must not repeat.
