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3 years ago

Use a graphing calculator to graph the function and its parent function. Then describe the transformations, f(x)=(x+3)+1/4

Mathematics

1 answer:

nlexa [21]3 years ago

8 0

Most of the graphing resources used shows that the graph is translated up by 3.25 (3 + 1/4). If you add the 3 and the 1/4, you get the equation of a line:

f(x) = x + 3.25,

which means that the graph of f(x)= x now has a y intercept of 3.25.

The graphs are below. The red line represents f(x) = x, and the green line represents (x+3)+1/4. Hope this helps!

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Given that f(x) = x2 – 14x + 45 and g(x) = 2 – 9, find f(x) – g(x) and

seropon [69]

Answer:

x2-14x+52 is the answer in my calculation.

8 0

3 years ago

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago

Latoya's annual salary is $26,000. A total of $7352.24 will be deducted for taxes and health insurance. She will receive her pay

Anna71 [15]

Step-by-step explanation:

Lets translate this word problem into math.

"Latoya's annual salary is $26,000" = We start with the number 26,000

"A total of $7352.24 will be deducted for taxes and health insurance" = It's the number we started with "deducted" (minus) 7352.24

"She will receive her paycheck monthly in 12 equal installments" = Our number will be divided by 12

"How much will she get paid with each paycheck?" = "Find answer pls thx"

To put it all together...

$\frac{26,000-7,352.24}{12}$

Now all we have to do is solve!

$\frac{26,000-7,352.24}{12}$

Subtract.

$\frac{18,647.76}{12}$

Divide.

$1,553.98$

Answer:

Latoya will get paid $1,553.98 with each paycheck.

7 0

3 years ago

3x+8 •59 solve for x

Marina86 [1]

1) Let's solve for x, writing this equation.

3x +8*59 =0

3x +472=0 <em>Subtract 472 from both sides</em>

3x = -472

x= -472/3 or -157.33

2) So the answer is x= -472/3

6 0

1 year ago

What is an algebraic expression

Bond [772]

An algebraic expression is an expression that includes constants, variables, and the algebraic operations (add, subtract, multiply, divide.

4 0

3 years ago

Use a graphing calculator to graph the function and its parent function. Then describe the transformations, f(x)=(x+3)+1/4​

Use a graphing calculator to graph the function and its parent function. Then describe the transformations, f(x)=(x+3)+1/4