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Katen [24]
3 years ago
15

I need help with writing a word problem that can be evaluated by the algebraic expression 372 + r, and evaluate it for r = 137.

Please help❤️
Mathematics
1 answer:
Soloha48 [4]3 years ago
4 0

Gabe had 372 apples and r grapes. The total of grapes and apples gabe has are 509. How many grapes did gabe have?


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Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3​
maria [59]

Answer:

        a_1=4\\\\a_2=0\\\\a_3=3

Explanation:

The equation is:

      a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}

and

      a_4=-7, a_5=-36, a_6=-85

<u>1. Subsittute n = 6 into the equation:</u>

      a_6=3a_{5}-5a_{4}-4a_{3}

      Now subsititute the known values:

       -85=3(-36)-5(-7)-4a_{3}

      You can solve for a_3

      -85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3

<u />

<u>2. Substitute n = 5 into the equation:</u>

    a_5=3a_{4}-5a_{3}-4a_{2}

     Substitute the known values and solve for a_2

        -36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0

<u>3. Substitute n = 4 into the equation, subsitute the known values and solve for </u>a_1<u />

       a_4=3a_{3}-5a_{2}-4a_{1}

        -7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4

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3 years ago
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Answer:

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Step-by-step explanation:

180-95-30=55

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Step-by-step explanation:

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A family of 2 adults and 3 children goes to a play Admission cost $8 per adult and $5 per child.What expression would show the t
alexdok [17]
[2x8]+[3x5]=31 that's the answer
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3 years ago
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Simplify the radical expression completely LaTeX: 3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}3 5 − 3 11 + 2 121 − 3 90 A. La
lora16 [44]

Answer:

3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

Step-by-step explanation:

Given

3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}

Required

Simplify the expression

3\sqrt{5}\:-\:3\sqrt{11}+2\sqrt{121}-3\sqrt{90}

Express the square root of 121 as 11

3\sqrt{5}\:-\:3\sqrt{11}+2 * 11-3\sqrt{90}

3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{90}

Express 90 as 9 * 10

3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9 * 10}

Split the surd to 2

3\sqrt{5}\:-\:3\sqrt{11}+22-3\sqrt{9} * \sqrt10}

Express the square root of 9 as 3

3\sqrt{5}\:-\:3\sqrt{11}+22-3 * 3 * \sqrt10}

3\sqrt{5}\:-\:3\sqrt{11}+22-9 * \sqrt10}

3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

Hence, the result of the expression is

3\sqrt{5}\:-\:3\sqrt{11}+22-9\sqrt{10}

7 0
3 years ago
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