Would a teaspoon be a good way to measure the capacity of a milk carton? Explain.

In quadrilateral ABDC, AB ∥ CD. Which additional piece of information is needed to determine that ABDC is a parallelogram?

N76 [4]

Since the definition of a parallelogram literally says that it's a quadrilateral with 2 parallel sides, we have AB || CD so the 2 other sides (AC and BD) need to be either similar or parallel (either works, due to that if they're similar we can prove that since AB || CD that they're parallel). B is our answer

3 0

3 years ago

Read 2 more answers

What is the image of (-6,-5) after a reflection over the -axis

AfilCa [17]

If the axis is x then you go to y so (6, 5)

7 0

3 years ago

Three quarters of the batch of twenty cookies burned when you forgot to take them out of the oven how many cookies burned

Natali5045456 [20]

15 cookies burned because if you Turn $\frac{3}{4}$ into a decimal then multiply it by 20 you get 15 and thats your answer.

7 0

3 years ago

What is the graph of linear inequality 2y>x-2

pickupchik [31]

Answer:

Please refer to the attached graph for the graph of linear inequality:

$2y>x-2$

Step-by-step explanation:

Method to draw graph of inequality:

1. First of all replace the inequality sign with equality.

Now the equation is:

$2y=x-2$

Now, find point and plot them.

Let us put x = 0, we get y = -1. So one point is (0, -1)

Let us put y = 0, we get x = 2. So one point is (2,0)

Now, plot both the point and join with straight line on xy coordinate axis.

2. Now, try to find a random point and put in the inequality.

If the point satisfies the inequality shade the region moving from the line towards that point.

For example:

Taking a point (4, 2)

Putting in the inequality:

$8 > 2-2 \\8>0$

So, (4, 2) satisfies the inequality.

Now, shade the region moving from the line towards the point (4,2).

We get the shaded region as shown in the attached figure in the answer area.

3 0

3 years ago

A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco

Brut [27]

Answer:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

$\bar X_{A}=48250$ represent the mean of elementary teachers

$\bar X_{B}=45630$ represent the mean for secondary teachers

$s_{A}=3900$ represent the sample standard deviation for elementary teacher

$s_{B}=5530$ represent the sample standard deviation for secondary teachers

$n_{A}=26$ sample size selected

$n_{B}=24$ sample size selected

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{B}\leq 0$

Alternative hypothesis: $\mu_{A}-\mu_{B}>0$

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{A}+n_{B}-2=26+24-2=48$

Since is a one sided test the p value would be:

$p_v =P(t_{(48)}>1.921)=0.0303$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0

3 years ago