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djverab [1.8K]
3 years ago
14

Hannah made 8 pints of lemonade how many glasses can she fill with 1/2 pint

Mathematics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

16

Step-by-step explanation:

half of one is 0.5 so times 8 by two and get 16

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What is the solution set of - lxl= -8?
NARA [144]

Answer:

8

Step-by-step explanation:

The absolute value of |x| is x

-x = -8

Distribute the - on the other side but since two negatives make a positive:

- and - = +

x = 8

Hope this helped.

6 0
3 years ago
The portion of line that falls between two points is call:
Fittoniya [83]
A, line segment : part of a line that is bounded by two distinct end points, and contains every point of the line between it's endpoints.
5 0
3 years ago
What are the roots of the equation? ​
IRISSAK [1]

Answer:

-8 and -3

Step-by-step explanation:

x^{2} +24=-11x

Add 11x to both sides;

x^{2} +11x+24=0\\\\(x+3)(x+8)=0

x + 3 = 0

Subtract 3 from both sides;

x = -3

x + 8 = 0

Subtract 8 from both sides;

x = -8

6 0
3 years ago
Read 2 more answers
20.Solve the triangle: b = 100, c = 100, y = 70". If it is not possible, say so.This triangle is not solvable.Q = 40", a = 68.4,
saveliy_v [14]

Answer:

\begin{gathered} \alpha=\text{ 40\degree} \\ \beta=\text{ 70\degree} \\ a=68.4 \end{gathered}

Step-by-step explanation:

By the theorem of intern angles of a triangle, we know that the sum of all intern angles of a triangle must be 180°, therefore:

*There are two equal angles because there are two equal sides

\begin{gathered} \alpha=180-70-70 \\ \alpha=\text{ 40\degree} \\ \beta=\text{ 70\degree} \end{gathered}

Now, applying the law of sines, we can find side a. The law of sines is represented by the following equation:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}

Hence, if b=100, alpha=40° and betha=70°, solve for a:

\begin{gathered} \frac{a}{\sin (40)}=\frac{100}{\sin (70)} \\ a=\frac{100\cdot\sin (40)}{\sin (70)} \\ a=\text{ 68.4} \end{gathered}

7 0
1 year ago
If tanA+cotA=2 then find the value of cosA​
aniked [119]

Answer:

cos A=

\frac{1}{ \sqrt{2} }

Step-by-step explanation:

We know,

cotA=

\frac{1}{ \tan(a) }

Substituting the value of cot A in the given equation, we get

\tan( a)  +  \frac{1}{ \tan(a) }  = 2

\frac{{ \tan }^{2} a + 1}{  \:  \tan(a)  }  = 2

{ \tan }^{2 \: } a \:  + 1 = 2 tan \: a

{ \tan }^{2} a - 2 \tan \: a + 1 = 0

( \tan \: a - 1) {}^{2 }  = 0

\tan \: a - 1 =  \sqrt{0}

\tan \: a = 1

\tan \: a \:  =  \tan \: 45

a = 45

\cos \: a =  \cos \: 45

\cos \: a =   \frac{1}{ \sqrt{2} }

4 0
3 years ago
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