Hey there! :)
2x + 4 > 16
We're simply just trying to get x onto it's own side, so let's get rid of any numbers on the same side of it.
We can start out by subtracting both sides by 4.
2x + 4 - 4 > 16 - 4
Simplify.
2x > 12
Then, divide both sides by 2.
2x ÷ 2 > 12 ÷ 2
Simplify.
x > 6
Therefore, our answer is D. x > 6
~Hope I helped!~
Answer:
Step-by-step explanation:
A. 221 x 5 = 1,105
225 + 245 + 222 +230 = 922
1,105 - 922 = <u>183</u>
B. 225 is the median
C. 229 is Isaac's score for the sixth game
Hope this helps :)
Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
<u>Solution:
</u>
Need to calculate
and then multiply the result by ![\sqrt[3]{14903}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D)
Let us first evaluate ![\sqrt[3]{1728}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1728%7D)
![\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12](https://tex.z-dn.net/?f=%5CRightarrow%20%5Csqrt%5B3%5D%7B1728%7D%3D%5Csqrt%5B3%5D%7B12%20%5Ctimes%2012%20%5Ctimes%2012%7D%3D12)
As need to multiply 12 by ![\sqrt[3]{14903}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D)
![\Rightarrow 12 \times \sqrt[3]{14903}](https://tex.z-dn.net/?f=%5CRightarrow%2012%20%5Ctimes%20%5Csqrt%5B3%5D%7B14903%7D)
On solving
, we get
![\sqrt[3]{14903}=24.608](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D%3D24.608)
![\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306](https://tex.z-dn.net/?f=%5CRightarrow%2012%20%5Ctimes%20%5Csqrt%5B3%5D%7B14903%7D%3D12%20%5Ctimes%2024.608%3D295.306)
Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
<h3>
Answer: Choice D. 
</h3>
This is because we want to avoid having negative numbers under the square root. So we make the radicand to be 0 or larger.
The +1 at the end doesn't affect the domain.
Answer:
D
Step-by-step explanation:
One number will be positive, and one will be negative