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mafiozo [28]
3 years ago
12

Joe Morris Plains to fertilize his 1800 foot wide Hayfield he will be using his truck spreader that spreads of 60-foot strip how

far from The Edge should you start​
Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0

Answer:

He should do 30 strips

Step-by-step explanation:60 times 3 is180 so and aa 0 to 180 and get 1800 so then you and the 0 to 3 and get 30

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Archy [21]

Answer:

A and C

<em>I hope this helps! ^^</em>

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8 0
2 years ago
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Please help me on the coke and the marathon one plzzzzzzzzzzzzzz!!.!!.,!!, thnx soooo much!!!
enyata [817]
The answer for the coke one is 46cents because you would do 2.76 divided by 6 and then for the marathon it would be 6.55 because u do 26.2 divided by 4 and get 6.55 hoped this helped
6 0
3 years ago
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The hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh
konstantin123 [22]

Answer:

33 copies were paperback and 12 were hardcover.

Step-by-step explanation:

Let h represent the number of hardcover copies and p represent the number of paperback copies.

We know that the total number of copies was 45; this gives us the equation

h+p = 45

We know that each hardcover copy is 7 ounces; this gives us the expression 7h.

We also know that each paperback copy is 5 ounces; this gives us the expression 5p.

We know that the total weight was 249 ounces; this gives us the equation

7h+5p = 249

Together we have the system

\left \{ {{h+p=45} \atop {7h+5p=249}} \right.

We will use elimination to solve this.  First we will make the coefficients of the variable p the same; to do this, we will multiply the top equation by 5:

\left \{ {{5(h+p=45)} \atop {7h+5p=249}} \right. \\\\\left \{ {{5h+5p=225} \atop {7h+5p=249}} \right.

To eliminate p, we will subtract the equations:

\left \{ {{5h+5p=225} \atop {-(7h+5p=249)}} \right. \\\\-2h=-24

Divide both sides by -2:

-2h/-2 = -24/-2

h = 12

There were 12 hardcover copies sold.

Substitute this into our first equation:

12+p=45

Subtract 12 from each side:

12+p-12 = 45-12

p = 33

There were 33 paperback copies sold.

3 0
3 years ago
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A lecture hall contains $20$ chairs, all lined in a row. What is the number of ways that five chairs can be chosen, so that no t
patriot [66]

Answer:

Step-by-step explanation:

If we choose chairs having odd number in the row

no of chairs from which selection is made = 10

no of chairs to be selected = 5

no of ways = 10C₅

similarly if we choose hairs having even numbers only ,

similar to above , no of ways

= 10C₅

Total no of ways

= 2 x 10C₅

= 2 x 10 x 9 x 8 x 7 x 6 / 5 x 4x3 x 2 x 1

= 504 .

6 0
3 years ago
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What is the value of s in the equation 4(2s − 1) = 7s + 12? (4 points)
notka56 [123]

Answer:

B) 16

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s-4=12

s=16

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3 years ago
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