All categories

3 years ago

Solve y 4y-17=43 simplify the answer

Mathematics

1 answer:

barxatty [35]3 years ago

3 0

4y-17=43

move -17 to the other side

sign changes from -17 to +17

4y-17+17=43+17

4y=43+17

4y=60

divide both sides by 4 to get y by itself

4y/4=60/4

answer:

y=15

You might be interested in

PLEASE HELP ASAP!!! 98 POINTS AND BRAINLIEST!!!

Setler [38]

Answer:

Part A. The slope of f(x) is 4. I observed that each time the y value would increase by 4 points every time the x value increases by 1. The slope of g(x) is 2. I identified the m value as it's in slope-intercept form. The slope of f(x) is greater then that of g(x) because 4>2

Part B. The y-intercept of f(x) is greater. It is given that when x is 0, y is -1, so the y intercept of f(x) is -1. Meanwhile, the y-intercept of g(x) is -7 after identifying the b value. -7<-1, concluding that f(x) has a greater y-intercept

Step-by-step explanation:

ty for the points

4 0

3 years ago

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating

MakcuM [25]

Answer:

A=8.4063 $u^{2}$

Step-by-step explanation:

Be the functions:

$y=\frac{3}{x};y=\frac{3}{x^{2}}:x=7$

according the graph:

$\int\limits^1_7 {\frac{3}{x} } \, dx -\int\limits^1_7 {\frac{3}{x^{2} } } \, dx =3\int\limits^1_7 {\frac{1}{x} } \, dx -3\int\limits^1_7 {\frac{1}{x^{2} } } \, dx=3(\int\limits^1_7 {\frac{1}{x} } \, dx -\int\limits^1_7 {\frac{1}{x^{2} } } \, dx)=3[lnx-\frac{1}{x}](1-7)=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}$

6 0

3 years ago

Please helppp with this math question <333

Naya [18.7K]

Answer:

The average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

Step-by-step explanation:

We are given the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$

We need to find average rate of change.

The formula used to find average rate of change is : $Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}$

We have b=-1 and a=-11

Finding g(b) = g(-1)

$g(x)=x^2+10x+18\\Putting \ x=-1\\g(-1)=(-1)^2+10(-1)+18\\g(-1)=1-10+18\\g(-1)=9$

Finding g(a) = g(-11)

$g(x)=x^2+10x+18\\Putting \ x=-11\\g(-11)=(-11)^2+10(-11)+18\\g(-1)=121-110+18\\g(-1)=29$

Finding average rate of change

$Average \ rate \ of \ change=\frac{g(b)-g(a)}{b-a}\\Average \ rate \ of \ change=\frac{9-29}{-1-(-11)}\\Average \ rate \ of \ change=\frac{-10}{-1+11}\\Average \ rate \ of \ change=\frac{-10}{10}\\Average \ rate \ of \ change=-1$

So, the average rate of change of the function $g(x)=x^2+10x+18$ over the interval $-11 \leq x\leq -1$ is -1

5 0

2 years ago

A manufacturer of chocolate chips would like to know whether its bag filling machine works correctly at the 404 gram setting. It

Nezavi [6.7K]

Answer:

There is no sufficient evidence to support the claim that the bags are underfilled

Step-by-step explanation:

We are given;

n = 27 bags

Sample mean;X = 402 gram

Population mean;μ = 404 gram

Variance = 676

We know that, standard deviation(σ) = √variance

Thus;

σ = √676

σ = 26

The hypotheses are;

Null hypothesis; H0: μ = 404

Alternative hypothesis; HA: μ < 404

Let's find the z-score from the formula;

z = (X - μ)/(√σ/n)

z = (402 - 404)/√(26/27)

z = -2.04

From the z-distribution table attached, we have a p-value of 0.02068

This is less than the significance value of 0.01 and thus we will reject the null hypothesis and conclude that there is no sufficient evidence to support the claim that the bags are underfilled

6 0

3 years ago

Helppppppppppppppppooop

Allisa [31]

It should be 715, i don’t understand why that isn’t one of the choices.
you’re supposed to multiply everything

4 0

2 years ago