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2 years ago

10

Draw a line through the origin that has a slope of negative 4/3

1 answer:

OleMash [197]2 years ago

8 0

The origin is just (0,0) and we can multiply that slope, -4/3 by any number to get the second point. let's use x=3 to make is simple as possible, the second point is then just (3,-4)

Connect (0,0) to (3,-4) and you have your line :)

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What is the sum of the rational expression below? 3x/x+2 + x/x+4

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2 years ago

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Step-by-step explanation:

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2 years ago

Which trigonometric ratio is correct for triangle DEF? (Hint: Use Pythagorean Theorem first) A.) Sin(D)= 24/7 B.) Tan(D)= 24/25

Tanya [424]

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Cos E= 24/25

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4 0

3 years ago

What are the coordinates of each point after quadrilateral ABCD is reflected across the y-axis and then translated 2 units down?

zheka24 [161]

Answer:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

Step-by-step explanation:

Given

$A = (1,1)$ $B =(2,3)$

$C = (4,3)$ $D = (5,1)$

Required

The new coordinates after reflected across y-axis and shifted 2 units down

When a point is reflected across the y-axis, the rule is:

$(x,y)=>(-x,y)$

So:

$A = (1,1)$ $=> A' = (-1,1)$

$B =(2,3)$ $=> B' = (-2,3)$

$C = (4,3)$ $=> C' = (-4,3)$

$D = (5,1)$ $=> D' = (-5,1)$

When a point is translated 2 units down, the rule is:

$(x,y) => (x,y-2)$

So:

$A = (1,1)$ $=> A' = (-1,1)$ $=> A" =(-1,-1)$

$B =(2,3)$ $=> B' = (-2,3)$ $=> B" =(-2,1)$

$C = (4,3)$ $=> C' = (-4,3)$ $=> C" =(-4,1)$

$D = (5,1)$ $=> D' = (-5,1)$ $=> D" =(-5,-1)$

So, the new coordinates are:

$A" =(-1,-1)$ $B" =(-2,1)$

$C" =(-4,1)$ $D" =(-5,-1)$

5 0

2 years ago