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3 years ago

Draw a line through the origin that has a slope of negative 4/3

1 answer:

8 0

The origin is just (0,0) and we can multiply that slope, -4/3 by any number to get the second point. let's use x=3 to make is simple as possible, the second point is then just (3,-4)

Connect (0,0) to (3,-4) and you have your line :)

You might be interested in

Consider the following ordered data. 6 9 9 10 11 11 12 13 14 (a) Find the low, Q1, median, Q3, and high. low Q1 median Q3 high (

IrinaVladis [17]

Answer:

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = 3.5

Step-by-step explanation:

Given that:

Consider the following ordered data. 6 9 9 10 11 11 12 13 14

From the above dataset, the highest value = 14 and the lowest value = 6

The median is the middle number = 11

For Q1, i.e the median of the lower half

we have the ordered data = 6, 9, 9, 10

here , we have to values as the middle number , n order to determine the median, the mean will be the mean average of the two middle numbers.

i.e

median = $\dfrac{9+9}{2}$

median = $\dfrac{18}{2}$

median = 9

Q3, i.e median of the upper half

we have the ordered data = 11 12 13 14

The same use case is applicable here.

Median = $\dfrac{12+13}{2}$

Median = $\dfrac{25}{2}$

Median = 12.5

Low Q1 Median Q3 High

6 9 11 12.5 14

The interquartile range = Q3 - Q1

The interquartile range = 12.5 - 9

The interquartile range = 3.5

7 0

3 years ago

Please help if possible. Thank you!

Shtirlitz [24]

Answer:15 pi

Step-by-step explanation:

The scope is 10(r)*2*pi

XPY is 3 quarters of the slope, which equals to 0.75*20*pi=15pi

6 0

3 years ago

Read 2 more answers

If LN = 12x + 16, what is the length of Line segment L N in units?

elena55 [62]

Answer:

LN = 64 units

Step-by-step explanation:

Given M lies on LN, so LN = LM + MN --------------(1)

LN = 12x + 16

LM = 10x + 8

MN = 5x - 4

Substituting the values in equation 1, we get:

12x + 16 = (10x + 8) + (5x - 4)

12x + 16 = 15x + 4

15x - 12x = 16 -4

3x=12

Therefore x=4

LN= 12(4) + 16 = 64 units

3 0

2 years ago

Please find the DIMENSIONS not the total area of both of these rectangles! I’m giving brainliest this is very urgent. Answers wo

7nadin3 [17]

Answer:

Question:14

3x4 (for the left square, 3 on the side(width) and 4 on the bottom(length))

3x9 (for the right square, 3 on the side(width) and 4 on the bottom(length))

3x13 (for the entire rectangle)

Question:15

3x10 (for the left, 3 on the side(width) and 10 on the bottom(length))

3x6 (for the right, 3 on the side(width) and 6 on the bottom(length))

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we

Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N( $\mu = 7 lbs , \sigma^{2} = 0.875^{2} lbs$ )

The standard normal z distribution is given by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean weight

n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{7.5-7}{\frac{0.875}{\sqrt{4} } }$ ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0

4 years ago