Question

When 24.68 grams of lithium nitrate (LiNO3) are produced, how many moles of lithium chloride (LiCI) reacted ?

Answer 1

0.3 moles of lithium chloride (LiCI) reacted to produce 24.68 grams of lithium nitrate (LiNO3).

Explanation:

Balanced equation for the reaction is:

2LiCl  + Pb(NO3)2 ⇒2 LiNO3 + PbCl2

Data given:

mass of LiNO3 produced = 24.68 grams

moles of LiCl reacted= ?

atomic mass of 1 mole of LiNO3 = 68.946 Grams

Number of moles = $\frac{mass}{atomic mass of one mole}$

putting the values in the above equation:

$\frac{24.68}{68.946}$

= 0.3 moles

from the reaction,

2 moles of LiCl reacted to form 2 moles of LiNO3

so, x moles of LiCl reacted to form 0.3 moles of LiNO3

$\frac{2}{2}$ = $\frac{0.3}{x}$

x = 0.3 moles of LiCl will react to form 0.3 moles of LiNO3.