Answer:
2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Explanation:
Given data:
Mass of sample = 142.1 g
Initial temperature = 25.5°C
Final temperature = 46°C
Specific heat capacity of Al = 0.90 J/g.°C
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 46°C - 25.5°C
ΔT = 20.5°C
Q = 142.1 × 0.90 J/g.°C × 20.5°C
Q = 2621.75 j
Thus, 2621.75 j heat is required to increase the temperature 25.5°C to 46°C.
Matter and substance are definitely related. All substances
are matter but all matters are not substance. A matter can consist of numerous
substances. Matter is generally a loose term used in respect to a substance.
Any physical object can be casually called a matter. Matter and substance are
sometimes used for the same context, but it is completely wrong. Numerous
examples have already proved that a matter may or may not be a substance
depending on its physical nature, but a substance is always a matter.
A calorimeter is just an insulated container which contains the sample. You combust the sample inside the calorimeter, then you measure the temperature with respect to time. Make sure to stir constantly. Thus, you need a thermometer and a stirrer. The coffee cup calorimeter is labelled as shown in the picture attached. The goal of this experiment is to determine the specific heat capacity.
Answer:
The concentration of H3O+= 0.15M
Explanation:
From The equation of reaction
HClO2(aq) + H2O(l) ⇌ H3O+(aq) + ClO2−(aq)
0.25mol HClO2(aq) 0.25mol producesClO2−(aq) and x-mol of H3O+
Using Kc = [H3O+][ClO2-]/[HClO2]
0.15= 0.25*x/0.25
Simplify
x=0.15M