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Ilya [14]
3 years ago
13

Which function has real zeros at x = 3 and x = 7?

Mathematics
1 answer:
german3 years ago
8 0
The answer is X2-10X+21

Explanation: If u put the equation in the graphing calculator 3 and 7 both equal zero meaning they are the x’s of the situation.
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The mean of 2.7, 3.6 and 1.8
kolezko [41]
Set them up from least to greatest..
The mean is the average of all the data so..
The answer is 2.7
8 0
4 years ago
Simplify
fiasKO [112]
The answer is d have a nice day
8 0
4 years ago
Read 2 more answers
Partial quotient for 654 divided by 3
Vladimir79 [104]

654 over 3 = divide the both 654 and 3 by 3.

It will give you 218 over 1.

So the answer is 218.

6 0
3 years ago
9n+21−3n−24 simplify
Thepotemich [5.8K]
Alright First you combine the like terms. 
9n - 3n = 6n 
21 - 24 = -3 

Rewrite the simplified equation
6n - 3 = 0

Solve for n 
6n = 3 
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Ask if you need more help! :)

6 0
3 years ago
PLEASE HELP ME!
kotegsom [21]

Answer:

Bottom left graph

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

−2x + y ≤ 4 >> Original Standard Equation

+ 2x + 2x

_________

y ≤ 2x + 4 >> Slope-Intercept Equation

−2[0] + 0 ≤ 4

0 ≤ 4 ☑ [We shade the part of the graph that CONTAINS THE ORIGIN, which is the right side.]

\displaystyle y > x + 2 \\ \\ 0 ≯ 2[We shade the part of the graph that does not contain the origin, which is the left side.]

So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], therefore the bottom left graph matches what we want.

** By the way, you meant \displaystyle y > x + 2because this inequality in each graph is a <em>dashed</em><em> </em><em>line</em>. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.

I am joyous to assist you anytime.

7 0
4 years ago
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