Help with this fast please

Mathematics

1 answer:

natta225 [31]4 years ago

7 0

Use the formula y2-y1/x2-x1

-3 - 0/ 4 - 16 = -3/-12 = 1/4

so the slope is 1/4

You might be interested in

You hammer a nail into a tree trunk 10 ft above the ground (and the tree is currently 20 ft tall). The tree grows taller at a ra

AnnZ [28]

Answer:

The nail would be 30 feet above the ground in 10 years.

Step-by-step explanation:

We are given the following in the question:

Height of nail = 10 feet.

The tree grows taller at a rate of 2 feet per year.

Thus, the height of nail can be represented by a linear function:

$h(t) = 10 + 2t$

where t is the number of years.

We have to find the height of nail in 10 years.

Putting t = 10, we get,

$h(10) = 10 + 2(10)\\h(10) = 30$

Thus, the nail would be 30 feet above the ground in 10 years.

3 0

4 years ago

Nadine's curtain company is making curtains for a local hotel. She wants each curtain to be 48 inches long. At the fabric store,

KonstantinChe [14]

Bsnsnssssa n jnsjssa sss

5 0

3 years ago

Using the pattern, give the coefficients of (x + y)^5 and (x + y)^6

musickatia [10]

Answer:

$(x+y)^5=x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$

$(x+y)^6=x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$

Step-by-step explanation:

In order to find the values of $(x+y)^5$ and $(x+y)^6$ , you need to apply the binomial theorem (high-level math you most likely don't need to worry about, it's easier than multiplying all the binomials together).

$(x+y)^5$ = $\sum _{i=0}^5\binom{5}{i}x^{\left(5-i\right)}y^i$ = $\frac{5!}{0!\left(5-0\right)!}x^5y^0+\frac{5!}{1!\left(5-1\right)!}x^4y^1+\frac{5!}{2!\left(5-2\right)!}x^3y^2+\frac{5!}{3!\left(5-3\right)!}x^2y^3+\frac{5!}{4!\left(5-4\right)!}x^1y^4+\frac{5!}{5!\left(5-5\right)!}x^0y^5$ = $x^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4+y^5$ .

$(x+y)^6$ = $\sum _{i=0}^6\binom{6}{i}x^{\left(6-i\right)}y^i$ = $\frac{6!}{0!\left(6-0\right)!}x^6y^0+\frac{6!}{1!\left(6-1\right)!}x^5y^1+\frac{6!}{2!\left(6-2\right)!}x^4y^2+\frac{6!}{3!\left(6-3\right)!}x^3y^3+\frac{6!}{4!\left(6-4\right)!}x^2y^4+\frac{6!}{5!\left(6-5\right)!}x^1y^5+\frac{6!}{6!\left(6-6\right)!}x^0y^6$ = $x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+y^6$ .