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3 years ago

11

You hammer a nail into a tree trunk 10 ft above the ground (and the tree is currently 20 ft tall). The tree grows taller at a ra

te of 2 feet per year. How far above ground level will the nail be in 10 years

1 answer:

AnnZ [28]3 years ago

3 0

Answer:

The nail would be 30 feet above the ground in 10 years.

Step-by-step explanation:

We are given the following in the question:

Height of nail = 10 feet.

The tree grows taller at a rate of 2 feet per year.

Thus, the height of nail can be represented by a linear function:

$h(t) = 10 + 2t$

where t is the number of years.

We have to find the height of nail in 10 years.

Putting t = 10, we get,

$h(10) = 10 + 2(10)\\h(10) = 30$

Thus, the nail would be 30 feet above the ground in 10 years.

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Write an equation (a) in slope-intercept form and (b) in standard form for the line passing through (-3,5) and parallel to x + 4

Dmitry [639]

Answer:

$\boxed{\sf Standard-form :x + 4y -17=0 }\\$

$\boxed{\sf Slope-intercept\ form :y =\dfrac{-1}{4}x +\dfrac{17}{4}}$

Step-by-step explanation:

Here a equation of the line is given to us and we need to find out the equation of line which passes through the given point and parallel to the given line , the given equation is ,

$\longrightarrow x + 4y = 7\\$

Firstly convert it into <em>s</em><em>l</em><em>o</em><em>p</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>e</em><em>r</em><em>c</em><em>e</em><em>p</em><em>t</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em> </em>of the line which is <u>y</u><u> </u><u>=</u><u> </u><u>m</u><u>x</u><u> </u><u>+</u><u> </u><u>x</u><u> </u>, as ;

$\longrightarrow 4y = -x + 7 \\$

$\longrightarrow y =\dfrac{-x}{4}+\dfrac{7}{4}\\$

On comparing it to <em>y</em><em> </em><em>=</em><em> </em><em>m</em><em>x</em><em> </em><em>+</em><em> </em><em>c</em><em> </em>, we have ,

$\longrightarrow m =\dfrac{-1}{4}\\$

$\longrightarrow c =\dfrac{7}{4}\\$

Now as we know that the <em>s</em><em>l</em><em>o</em><em>p</em><em>e</em><em> </em><em>o</em><em>f</em><em> </em><em>t</em><em>w</em><em>o</em><em> </em><em>p</em><em>a</em><em>r</em><em>a</em><em>l</em><em>l</em><em>e</em><em>l</em><em> </em><em>l</em><em>i</em><em>n</em><em>e</em><em>s</em><em> </em><em>i</em><em>s</em><em> </em><em>s</em><em>a</em><em>m</em><em>e</em><em> </em>. Therefore the slope of the parallel line will be ,

$\longrightarrow m_{||)}=\dfrac{-1}{4}\\$

Now we may use <em>p</em><em>o</em><em>i</em><em>n</em><em>t</em><em> </em><em>s</em><em>l</em><em>o</em><em>p</em><em>e</em><em> </em><em>f</em><em>o</em><em>r</em><em>m</em><em> </em>of the line as ,

$\longrightarrow y - y_1 = m(x-x_1) \\$

On substituting the respective values ,

$\longrightarrow y - 5 =\dfrac{-1}{4}\{ x -(-3)\}\\$

$\longrightarrow y -5=\dfrac{-1}{4}(x+3)\\$

$\longrightarrow 4(y -5 ) =-1(x +3) \\$

$\longrightarrow 4y -20 = - x -3 \\$

$\longrightarrow x + 4y -20+3=0\\$

$\longrightarrow \underset{Standard \ Form }{\underbrace{\underline{\underline{ x + 4y -17=0}}}} \\$

Again the equation can be rewritten as ,

$\longrightarrow y - 5 = \dfrac{-1}{4}(x +3) \\$

$\longrightarrow y = \dfrac{-1}{4}x -\dfrac{3}{4}+5 \\$

$\longrightarrow y = \dfrac{-1}{4}x -\dfrac{20-3}{4} \\$

$\longrightarrow \underset{Slope-Intercept\ form }{\underbrace{\underline{\underline{ y =\dfrac{-1}{4}x +\dfrac{17}{4}}}}}\\$

6 0

2 years ago

Solve for x<br> (1/x) -2/3 = (4x)

Vadim26 [7]

The value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

Step-by-step explanation:

The equation is $\frac{1}{x}-\frac{2}{3}=4 x$

Subtracting by $4x$ on both sides,

$\frac{1}{x}-\frac{2}{3}-4 x=0$

Taking LCM,

$\frac{3-12 x^{2}-2 x}{3 x}=0$

Multiplying by 3x on both sides,

$-12 x^{2}-2 x+3=0$

Dividing by (-) on both sides,

$12 x^{2}+2 x-3=0$

Using quadratic formula, we can solve for x.

$\begin{aligned}x &=\frac{-2 \pm \sqrt{2^{2}-4 \cdot 12 \cdot(-3)}}{2 \cdot 12} \\&=\frac{-2 \pm \sqrt{4+144}}{2 \cdot 144} \\&=\frac{-2 \pm \sqrt{148}}{24} \\&=\frac{-2 \pm 2 \sqrt{37}}{24}\end{aligned}$

Taking out common term 2, we get,

$\begin{array}{l}{x=\frac{-2(1 \pm \sqrt{37})}{24}} \\{x=\frac{-1 \pm \sqrt{37}}{12}}\end{array}$

Thus, the value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

4 0

3 years ago

PLZ HELP E!!!!!!! WILL MARK BRAINLIEST

vitfil [10]

Answer:

1

+

sec

2

(

x

)

sin

2

(

x

)

=

sec

2

(

x

)

Start on the left side.

1

+

sec

2

(

x

)

sin

2

(

x

)

Convert to sines and cosines.

Tap for more steps...

1

+

1

cos

2

(

x

)

sin

2

(

x

)

Write

sin

2

(

x

)

as a fraction with denominator

1

.

1

+

1

cos

2

(

x

)

⋅

sin

2

(

x

)

1

Combine.

1

+

1

sin

2

(

x

)

cos

2

(

x

)

⋅

1

Multiply

sin

(

x

)

2

by

1

.

1

+

sin

2

(

x

)

cos

2

(

x

)

⋅

1

Multiply

cos

(

x

)

2

by

1

.

1

+

sin

2

(

x

)

cos

2

(

x

)

Apply Pythagorean identity in reverse.

1

+

1

−

cos

2

(

x

)

cos

2

(

x

)

Simplify.

Tap for more steps...

1

cos

2

(

x

)

Now consider the right side of the equation.

sec

2

(

x

)

Convert to sines and cosines.

Tap for more steps...

1

2

cos

2

(

x

)

One to any power is one.

1

cos

2

(

x

)

Because the two sides have been shown to be equivalent, the equation is an identity.

1

+

sec

2

(

x

)

sin

2

(

x

)

=

sec

2

(

x

)

is an identity

Step-by-step explanation:

7 0

3 years ago

Is 1+4(3x-10)-12x equivalent to-9

Ymorist [56]

Answer:

no

Step-by-step explanation:

Given

1 + 4(3x - 10) - 12x ← distribute the parenthesis

= 1 + 12x - 40 - 12x ← collect like terms

= 1 - 40

= - 39 ≠ - 9

5 0

3 years ago

The difference of the quotient m and 9 and the quotient of n and 30

Zanzabum

Answer: (30m-9n)/270

First we start with m/9-n/30.

We multiply the denominators to get 270.

Then we multiply the numerators by the original denominators to get (30m-9n).

To check, we can use m=2, and n=4

2/9-4/30=4/45

(30*2-9*4)/270=24/270=4/45

5 0

3 years ago