A pressure system is a relative peak or lull in the sea level pressure distribution. The surface pressure at sea level varies minimally, with the lowest value measured 87 kilopascals (26 inHg) and the highest recorded 108.57 kilopascals (32.06 inHg). High- and low-pressure systems evolve due to interactions of temperature differentials in the atmosphere, temperature differences between the atmosphere and water within oceans and lakes, the influence of upper-level disturbances jargon as well as the amount of solar heating or radiational cooling an area receives. Pressure systems cause weather experienced locally. Low-pressure systems are associated with clouds and precipitation that minimize temperature changes through the day, whereas high-pressure systems normally associated with dry weather and mostly clear skies with larger diurnal temperature changes due to greater radiation at night and greater sunshine during the day. Pressure systems are analyzed by those in the field of meteorology within surface weather maps.
Answer: E = 5.80*10^-13 J
Explanation:
Given
We use the law of conservation of momentum to solve this
Momentum before breakup = momentum after breakup
0 = m1v1 + m2v2
0 = 238m * -2.2*10^5 + 4m * v2
0 = -523.6m m/s + 4m * v2
v2 * 4m = 523.6m m/s
v2 = 523.6 m m/s / 4m
v2 = 130.9*10^5 m/s
v2 = 1.31*10^7 m/s
Using this speed in the energy equation, we have
E = 1/2m1v1² + 1/2m2v2²
E = 1/2 * (238 * 1.66*10^-27) * -2.2*10^5² + 1/2 * (4 * 1.66*10^-27) * 1.31*10^7²
E = [1/2 * 3.95*10^-25 * 4.84*10^10] + [1/2 * 6.64*10^-27 * 1.716*10^14]
E = (1/2 * 1.911*10^-14) + (1/2 * 1.139*10^-12)
E = 9.56*10^-15 + 5.7*10^-13
E = 5.80*10^-13 J
Answer:
0.255
Explanation:
The following data were obtained from the question:
Force (F) = 57 N
Mass (m) = 22.8 Kg
Coefficient of static friction (µ) =...?
Next, we shall determine the normal reaction (R). This is illustrated below:
Mass (m) = 22.8 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (R) =?
R = mg
R = 22.8 x 9.8
R = 223.44 N
Finally, we can obtain the coefficient of static friction (µ) as follow:
Force (F) = 57 N
Normal reaction (R) = 223.44 N
Coefficient of static friction (µ) =...?
F = µR
57 = µ x 223.44
Divide both side by 223.44
µ = 57/223.44
µ = 0.255
Therefore, the coefficient of static friction (µ) is 0.255.
Answer:
Explanation:
The electronic configuration of many ions is that if a closes noble gas to them in a periodic table.
An Anion is a ion that has gained one or more electron, acquiring a negative charge.
A Cation is a ion that has lost one or more electron, gaining a positive charge.
