Answer: 44.57°C
Explanation:
The following can be deduced from the question:
Specific heat of water = 4.186 J/kg
From the question, we can infer that 625 × 4.186 joules of heat will be lost when there's a 1°C drop of water.
We then calculate the amount if degrees that it'll take to cool for 7.96 x 10⁴J. This will be:
= 7.96 × 10⁴ /(625 × 4.186)
= 79600/(625 x 4.186)
= 79600/2616.25
= 30.43°C
The final temperature will then be:
= 75.0°C - 30.43°C
= 44.57°C
Answer:
The magnitude of the force the garbage exerts on the floor of the service elevator is 12 N
Explanation:
Given;
mass of the garbage, m = 10.0 kg
acceleration of the elevator, a = 1.2 m/s²
The magnitude of the force the garbage exerts on the floor of the service elevator is given by;
F = ma
F = 10 x 1.2
F = 12 N
Therefore, the magnitude of the force the garbage exerts on the floor of the service elevator is 12 N
Answer:
The straight line that is obtained, intercept it on the y-axis and the value of displacement will obtained.
Explanation:
Answer:
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Explanation:
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The formula to find work is

. In this case, the force exerted on the rock is 15 Newtons and the distance the rock moved was 2 meters, so 15 * 2 = 30. The answer to your question is
D) 30 n-m.