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LUCKY_DIMON [66]
2 years ago
10

I need help ASAP :(((

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
5 0

Answer:

D

Step-by-step explanation:

1%

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Help me with this problem I've been working on it for a while now and just can't figure it out
Serggg [28]
1. Write out the problem: 3x+12/3

2. Find the common factor: 3(x+4)/3

3. Cancel out the threes.

4. Once you cancel them out you get: x+4

Hope I could help. Have a great day!:-)))
7 0
3 years ago
What’s the x and y intercepts of this equation: -3x-7y=84
Arlecino [84]

Answer:

The X and Y intercepts to the equation -3x - 7y = 84 is

x-intercept (s): (−28,0)

y-intercept (s): (0,−12)

Step-by-step explanation:

To find the x-intercept(s), substitute in 0 for y and solve for x

−3x−7⋅0=84

Solve the equation.

x=−28

x-intercept(s) in point form.

x-intercept (s): (−28,0)

To find the y-intercept(s), substitute in 0 for x and solve for y .

−3⋅0−7y=84

Solve the equation.

y=−12

y-intercept(s) in point form.

y-intercept (s): (0,−12)

Hope this helps.

4 0
3 years ago
Use the distributive property to write an expression equivalent to 5×(3+4)​
Lubov Fominskaja [6]
The answer is 5x times 7
8 0
3 years ago
A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d
Alenkasestr [34]

Answer:

μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

<em>Distance 1:</em>

- Ff*d₁ = Ef - Ei

⇒  - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ  

⇒   - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ   <em>(I)</em>

 

<em>Distance 2:</em>

<em />

- Ff*d₂ = Ef - Ei

⇒  - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒   μ*g*d₂ = 0.5*v²     <em>(II)</em>

<em />

<em>If we apply (I) + (II)</em>

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

 ⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ   <em>  (III)</em>

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁   ⇒   vf² = 2*g*Sin θ*d₁ = v²

then (from the equation <em>III</em>) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒  μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒   μ =  Sin θ * d₁ / (d₂ - Cos θ*d₁)

b)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK   ⇒   - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁   ⇒   d₂ = Sin θ*d₁ / μ

3 0
3 years ago
Which quadrilateral is a kite?
ollegr [7]

Answer:

The answer's B.

Step-by-step explanation:

I just took the test.

Quadrilateral EFGH is the only quadrilateral that fits the specifications for a kite. A kite has two pairs of adjacent sides that are congruent and opposite sides that are not congruent.

8 0
3 years ago
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