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arlik [135]
3 years ago
7

270 american dollar and recevied 3000 pesos when he returned from mexico he had 100 pesos left. how many will he recevie when he

exchanges these pesos for dollars
Mathematics
1 answer:
AURORKA [14]3 years ago
7 0
To solve this problem we can use simple proportion
If 
270$ -------------------------3000 pesos
x $  ---------------------------100 pesos               (x$ means that we dont know how much)
Now we crossmultiplying to get proportion
x*3000=270*100
Now we just to solve eq
3000x=27000  /:3000
x=27000:3000
x=9$ - its the result
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A investor obtained a loan of $600,000 to buy a car wash business. The monthly mortgage payment was based on 30 years at 5.5%. F
Lisa [10]

Answer:

The monthly mortgage payment is $ 8306.58

Step-by-step explanation:

Given as :

The loan taken as $ 600,000

The rate of interest = 5.5 %

The time period = 30 Years

So, from compounded method

Amount = principal × (1 +\frac{Rate}{100})^{Time}

or, Amount = $ 600,000 × (1 +\frac{5.5}{100})^{30}

Or, Amount =  $ 600,000 × (1.055)^{30}

∴   Amount = $ 2990370.77

<u>Now for The monthly mortgage payment </u>

∵ Time period is 30 years

So , 30 years = 12 × 30 = 360 months

∴ Amount payment in monthly =$ \frac{2990370.77}{360}

Or, Amount payment in monthly =$ 8306.58

Hence The monthly mortgage payment is $ 8306.58   Answer

4 0
3 years ago
36(pi) cubed divides by (pi) 3 squared
AleksAgata [21]
Answer in decimal form: 37.69911184
5 0
3 years ago
Plsss help I need answers by today
pentagon [3]

Answer:

E, A, F

Step-by-step explanation:

3 0
2 years ago
Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu
olchik [2.2K]

Answer:

a) s^2 =30^2 =900

b) \frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

c) 23.818 \leq \sigma \leq 41.112

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in  the variability in the number of rooms occupied per day during a particular season of the  year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per  day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

s^2 =30^2 =900

Part b

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom are given by:

df=n-1=20-1=19

Since the Confidence is 0.90 or 90%, the significance \alpha=0.1 and \alpha/2 =0.05, the critical values for this case are:

\chi^2_{\alpha/2}=30.144

\chi^2_{1- \alpha/2}=10.117

And replacing into the formula for the interval we got:

\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}

567.28 \leq \sigma^2 \leq 1690.224

Part c

Now we just take square root on both sides of the interval and we got:

23.818 \leq \sigma \leq 41.112

5 0
3 years ago
Please help me i have 1 more after this
Zinaida [17]

Answer:

11

Step-by-step explanation:

24 -:- 3+3

8+3

11

7 0
3 years ago
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