Explain how you can identify a linear non-proportional relationship from a table, a graph, and an equation.

Alright to the nearest 100th now

kirill [66]

Answer:

28.26

Step-by-step explanation:

For this, we can simply use the pi times r squared because we have the radius.

simplify pi to 3.14, so we can do 3.14 times 3 squared.

we get 9x 3.14, which is 28.26.

8 0

3 years ago

Find the value of x.

podryga [215]

Answer:

x=17

Step-by-step explanation:

the two segements equal each other, so make teh equations equal eachother and solve for x ,2x-10=x+7

4 0

4 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = 7x6, y

IgorC [24]

Answer:

The volume is $\frac{490\pi}{39}$ cubic units.

Step-by-step explanation:

The given curve is

$y=7x^6$

The given line is

$y=7x$

Equate both the functions to find the intersection point of both line and curve.

$7x^6=7x$

$7x^6-7x=0$

$7x(x^5-1)=0$

$7x=0\rightarrow x=0$

$x^5-1=0\rightarrow x=1$

According to washer method:

$V=\pi \int_{a}^{b}[f(x)^2-g(x)^2]dx$

Using washer method, where a=0 and b=1, we get

$V=\pi \int_{0}^{1}[(7x)^2-(7x^6)^2]dx$

$V=\pi \int_{0}^{1}[49x^2-49x^{12}]dx$

$V=49\pi \int_{0}^{1}[x^2-x^{12}]dx$

$V=49\pi [\frac{x^3}{3}-\frac{x^{13}}{13}]_0^1$

$V=49\pi [\frac{1^3}{3}-\frac{1^{13}}{13}-(0-0)]$

$V=49\pi [\frac{1}{3}-\frac{1}{13}]$

$V=49\pi (\frac{13-3}{39})$

$V=49\pi (\frac{10}{39})$

$V=\frac{490\pi}{39}$

Therefore the volume is $\frac{490\pi}{39}$ cubic units.

5 0

3 years ago

Which of the following rational functions is graphed below?

Mars2501 [29]

Answer:

Option B.

Step-by-step explanation:

We can see that we have an asymptote at x = 2

Remember that in a rational function, the asymptote is at the x-value such that the denominator is equal to zero.

So, the denominator is something like:

(x + a)

we have that the denominator is zero when x = 2

Then:

(2 + a) = 0

solving that for a, we get:

a = -2

Then the denominator of the rational function is:

(x - 2)

For the given options, the only one with this denominator is option B, then the correct option is B.

6 0

3 years ago

A quadratic function f(x)f(x) is hidden from view. You must find the xx-intercept(s) of f(x)f(x) and write the answer(s) in the

Alika [10]

f(x) should be in canonical form. So it must have the form

$f(x)=a(x-x_v)^2+y_v$

Where a is the main coefficient and is the vertex

Step-by-step explanation:

A quadratic function has a unique extreme value in its vertex. That value might be a maximum or a minimum depending on the sign of the main coefficient of the quadratic function. In order to quickly obtain the vertex, the quadratic must be written in canonical form. That means that f(x) must have the form

$f(x)=a(x-x_v)^2+y_v$

Where a is the main coefficient (which should be negative so that a minimum exists in the first place) and is the vertex. If f(x) is written in that form, then it will be easier to find the minimum of f(x), which is the vertex

Hence for the quadratic function below

$\begin{gathered} f(x)=(x-2)^2-9 \\ f(x)=x^2-4x-5 \\ ax^2+bx+c \\ a=1,\text{ b=-4, c=-5} \\ x_v=-\frac{b}{2a} \\ x_v=\frac{-(-4)}{2(1)} \\ x_v=\frac{4}{2} \\ x_v=2 \\ y_v=2^2-4(2)-5 \\ y_v=-9 \\ (x,y)\longrightarrow(2,-9) \end{gathered}$

Hence there is only one x- intercept and answer is (2, -9)

7 0

2 years ago