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3 years ago

Factor the GCF: 28a^3b^4 + 20a^2b^2 − 16ab^3.

Mathematics

1 answer:

9966 [12]3 years ago

7 0

D. 4ab(7a^2b^3+5a-4b^3)

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Is 289 prime? I need this asap (provide factor tree)

antiseptic1488 [7]

Answer: 289 is a semi-prime number that is created by doing 17 times 17. 17 is a prime number though. hope this helps.

Step-by-step explanation:

289

17 17

6 0

3 years ago

Approximate f by a Taylor polynomial with degree n at the number a. Step 1 The Taylor polynomial with degree n = 3 is T3(x) = f(

MAVERICK [17]

Answer:

If you center the series at x=1

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

Step-by-step explanation:

From the information given we know that

$f(x) = e^{2x^2}$

$f'(x) = 4x e^{2x^2}$ (This comes from the chain rule )

$f^{(2)}(x) = 4e^{2x^2} (4x^2+1)$ (This comes from the chain rule and the product rule)

$f^{(3)}(x) = 16xe^{2x^2}(4x^2 + 3)$ (This comes from the chain rule and the product rule)

If you center the series at x=1 then

$T_3(x) = e^2 + 4e^2 (x-1)+10(x-1)^2 + \frac{56}{3} e^2(x-1)^3 + R(x)$

Where $R(x)$ is the error.

3 0

2 years ago

How do I solve this question?

Sati [7]

Answer:

m=2 and n=3

Step-by-step explanation:

<u>Step</u> :-

Given $[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

using algebraic formula $(a^m)^n= a^{mn}$

now

$2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}$

now equating 'x' powers, we get

$x^{mn} = x^{6}$

$mn=6$ ....(1)

now

$y^{2m} = y^{4}$

Equating 'y' powers ,we get

2 m=4

m=2

substitute m= 2 in equation (1)

we get

2 n=6

n=3

verification:-

substitute m=2 and n=3 , we get

$[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4$

$(2 x^{3} y^2)^2 = 4 x^6 y ^4\\$

$4 x^6 y^4 = 4 x^6 y^4$

both are equating so m= 2 and n=3

4 0

2 years ago

Pls help me on this k12 question.

andrew-mc [135]

Answer: The answer is A, 132 units

Step-by-step explanation:

8 0

2 years ago

Which statement is true about the radical expression square root of 25

Lena [83]

Answer:

Step-by-step explanation:

The square Root of 25 in its simplest form means to get the number 25 inside the radical √ as low as possible.

25 is a perfect square, which means that you can simply calculate the square Root of 25 to get the answer. 5 times 5 equals 25. Thus, the square Root of 25 in simplest radical form is = 5

3 0

3 years ago