Answer:
$94.50
Step-by-step explanation:
you saved $31.50
Answer: M(2) = $1500*(1 - 0.026)^2 = $1423.01
Step-by-step explanation:
Initially in the acount there is $1500
You lose a 2.6% (or 0.026 in decimal form) per year, so after the first year you have:
M = $1500 - 0.026*$1500 = $1461
After other year, you lose oter 2.6%
M = $1461 - 0.026*$1461 = $1423.01
The equation can be writen as:
M(t) = $1500*(1 - 0.026)^t
Where t is the number of years, you can use t = 2 and get:
M(2) = $1500*(1 - 0.026)^2 = $1423.01
Slope = (y2 - y1)/(x2 - x1)
slope = (7 - -2)/(-3 - 6)
slope = 9/-9
slope = -1
Answer:
Step-by-step explanation:
g(5) = 5^2 - 4 = 25 - 4 = 21
f(21) = 5(21) + 2 = 105 + 2 = 107
Answer:
P(cell has at least one of the positive nickel-charged options) = 0.83.
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.
Step-by-step explanation:
It is given that the Nickel Charge Proportions found in the battery are:
0 ==> 0.17
.
+2 ==> 0.35
.
+3 ==> 0.33
.
+4 ==> 0.15.
The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.
a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.
Or:
P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.
b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)
= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3
= 1 - 0.15
= 0.85
To summarize:
P(cell has at least one of the positive nickel-charged options) = 0.83!!!
P(a cell is not composed of a positive nickel charge greater than +3) = 0.85!!!
