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3 years ago

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Frank’s quarter grades are 82.5, 94.7, and 87.9. What grade, rounded to the nearest percent, will Frank have to earn in the last

quarter to receive at least a 90% final course grade? A. 93% B. 95% C. 94% D. 92%

1 answer:

Fynjy0 [20]3 years ago

4 0

B, because it would have to be at least a 94.9, which rounds up to 95

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Determine the 10th term from the end of the AP 4, 9, 14

77julia77 [94]

Answer:

<h2>The answer is 49</h2>

Step-by-step explanation:

Since the sequence above is an arithmetic sequence

For an nth term in an arithmetic sequence

A(n) = a + ( n - 1)d

where a is the first term

n is the number of terms

d is the common difference

To find the 10th term of the sequence first find the first term and the common difference

From the question

a = 4

d = 9 - 4 = 5 or 14 - 5 = 9

Since we are finding the 10th term

n = 10

Substitute the values into the above formula

That's

A(10) = 4 +(10-1)5

= 4 + 9(5)

= 4 + 45

We have the final answer as

<h3>A(10) = 49</h3>

Hope this helps you

6 0

3 years ago

-2x + 5 (1 -7x ) =190

luda_lava [24]

The answer is x= -5 ...explained... -2x + 5 -35x= 190...-37x +5 = 190 ... now subtract 190-5 = 185... divide 185 by - 37 and get -5

8 0

3 years ago

Try this B E Given: BELO, BOLE Prove ABEL ALOB Complete the Proof Statements 1. 2. BO=LE 3. 4. ∆BEL =∆LOB REASONS 1.GIVEN 2. 3.

AnnZ [28]

The given congruency of the sides $\mathbf{\overline{BE}}$ and $\mathbf{\overline{LO}}$ and $\mathbf{\overline{BO}}$ and $\mathbf{\overline{LE}}$ as well

as the congruency of the common side $\mathbf{\overline{BL}}$ gives.

ΔBEL ≅ ΔLOB by SSS congruency postulate

<h3>Which values correctly completes the table?</h3>

The completed two column proof is presented as follows;

Statement ${}$ Reasons

1. $\underline{\overline{BE} \cong \overline{LO}}$ ${}$ 1. Given

2. $\overline{BO}$ ≅ $\overline{LE}$ ${}$ 2.

3. $\underline{\overline{BL} \cong \overline{BL}}$ ${}$ 3. <u>Reflexive property of congruency</u>

4. ΔBEL ≅ ΔLOB ${}$ 4. <u>SSS congruency postulate</u>

Side-Side-Side, SSS, congruency postulate states that if three sides of

one triangle are congruent to three sides of another triangle, the two

triangles are congruent.

Learn more about different congruency postulates here:

brainly.com/question/1495556

7 0

2 years ago

Question 2 pleaseee !!!!!!

Leya [2.2K]

It’s 40 degrees
I subtracted 180 minus the 150 and got 30 then addd 110 and 30 and got 140 then substractef that from 180 and got 40

4 0

3 years ago

A genetics experiment involves a population of fruit flies consisting of 1 male named Bart and 3 females named Charlene, Diana,

kenny6666 [7]

Answer:

(b) $\frac{1}{2}$

Step-by-step explanation:

1 male named Bart (b)

3 females named Charlene(c), Diana(d), and Erin(e).

Since there is replacement, the possible samples are:

bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.

Total Number of pairs = 16

Event of picking 2 males:bb

Event of 1 male:bc,cb,bd,db,be,eb

Event of picking 0 males:

cc, cd, ce, dc, dd, de, ec, ed, and ee.

$\begin{equation*} \begin{matrix}Proportion of males & Probability \\0 & 9/16 \\1 & 6/16 \\2 & 1/16 \end{matrix} \end{equation*}$

b. The mean of the sampling distribution

$\mu = (\frac{9}{16} X0 ) +(\frac{6}{16} X 1)+(\frac{1}{16} X 2) = \frac{8}{16} = \frac{1}{2}$

c. No; the proportion of males is $\frac{1}{4}$ while the mean is $\frac{1}{2}$ .

B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.

7 0

3 years ago