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Feliz [49]
3 years ago
5

At the shorter waterfall, water falls uninterrupted for 1552 feet before entering the river below. The height h above the river

in feet of water going over the edge of the waterfall is modeled by h\left(t\right)=-16t^2+1552h(t)=−16t^2+1552, where is the time in seconds after the initial fall. Estimate the time it takes for the water to reach the river. Round your answer to the nearest tenth.
Mathematics
1 answer:
qwelly [4]3 years ago
8 0

Answer:

<h3>9.9s</h3>

Step-by-step explanation:

First note that the river is on the ground level. The height of the river at the ground level is 0

Given the the height h above the river in feet of water going over the edge of the waterfall is modeled by h(t)=-16t^2+1552

When h = 0

0 = -16t^2+1552

16t^2 = 1552

t² = 1552/16

t² = 97

t = √97

<em>t = 9.9secs</em>

<em>Hence the time it takes is 9.9secs to the nearest tenth</em>

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