If the question is to find the slope-intercept form of both lines, here's the answer: Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point. Let's first apply all these for the first line, with a slope of 4. y = mx + b y=-3; x=-4; m=4. All we need to do is find b. -3 = 4(-4) + b -3 = -16 + b b=13 So the equation of the first line is y= 4x + 13.
Now, we'll do the same thing but for the second line: y=-3; x=-4; m=-1/4, and we need to find b. -3 = (-1/4)(-4) + b -3 = 1 + b b= -4 So the equation of the second line is y=(-1/4)x - 4
