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aleksley [76]
3 years ago
13

Giving brainliest and max rating.

Mathematics
1 answer:
Yanka [14]3 years ago
8 0

Given:

The cost of each carnival ticket is $5.

To find:

The equation, table of values and graph for the given problem.

Solution:

Let x be the number of tickets and y be the total money spent on tickets.

Cost of one ticket = $5

Cost of x tickets = $5x

So, total cost is

y=5x

The required equation is y=5x.

At x=1,

y=5(1)

y=5

At x=2,

y=5(2)

y=10

At x=3,

y=5(3)

y=15

The required table of values is

x       y

1        5

2      10

3      15

So, the required table of values is table A.

From the above table, it is clear that the graph passes through the point (1,5), (2,10) and (3,15). The graph B passes through these points.

So, the required graph is graph B.

Since the required answers are y=5x, table A, graph B, therefore the correct option is B.

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mars1129 [50]

Answer:

22.62

Step-by-step explanation:

Cos=12/13

12/13= 0.9231

Cos^-1(0.9231)=22.62

8 0
3 years ago
2x10=<br> is equal to what ?
s2008m [1.1K]

Answer:

20

Step-by-step explanation:

2×10=20

Or...

10+10=20

4 0
3 years ago
Read 2 more answers
(p²-pq + q²) ( 3p+ 3q) ​
RUDIKE [14]

Answer:

3p^3 + qp^2 - pq^2 + 3q^3

Step-by-step explanation:

(p²-pq + q²) ( 3p+ 3q)

3p^3 + 3qp^2 - 3qp^2 - 3pq^2 + 3pq^2 + 3q^3

3p^3 + qp^2 - pq^2 + 3q^3

3 0
3 years ago
A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po
Mariana [72]

Answer:

The work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

Step-by-step explanation:

The work is defined by:

W=\int dFdx (1)    

The force here will be the product between the volume and the kerosene weighing, so we have :

dF=\pi R^{2}dy*50

This force will be in-lbs.

Where R is the radius (3 feet)                    

Then using (1), we have:

W=\int \pi R^{2}dy*50(8-y)  

Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.

W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)

W=450\pi \int_{0}^{8}dy(8-y)

W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)

W=450\pi(8y|_{0}^{8} -\frac{y^{2}}{2}|_{0}^{8})  

W=450\pi(8*8 -\frac{8^{2}}{2})

W=450\pi(64 -\frac{64}{2})

Therefore, the work done to  pump all of the kerosene from the tank to an outlet is W=45238.9\: J  

I hope it helps you!  

6 0
3 years ago
Asap! find the length of the arc
Fantom [35]

<u>Answer</u>:

A.  \frac{21}{4} \pi\ \space\ in

<u>Step-by-step explanation:</u>

The formula for arc length is:

arc length = rθ

where:

r is the radius = 7 in

θ is the central angle in radians = 135  ×  \frac{ \space\ \pi\ }{180}  = 3/4 π

Substituting these values into the formula:
arc length = 7 in × 3/4 π

                 = \frac{21}{4} \pi\ \space\ in

                             

6 0
2 years ago
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