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3 years ago

8

the temperature increased -3 C in the morning to 5 C in the afternoon. how many degrees did the temperature change? (please expl

ain)

1 answer:

algol133 years ago

6 0

46.4 degrees or if you don't need the .4 just put 46 or if you need it in C then it went up 8 C

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Which student evaluated the power correctly?

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Just plug in the calculator and see which

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3 years ago

Maria was playing a game with her brother. she said,”I’m thinking of a number. When you multiply my number by six and add seven,

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4 years ago

A kilogram is 1,000 times as large as a gram. is it true or false

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3 years ago

At a Noodles & Company restaurant, the probability that a customer will order a nonalcoholic beverage is .51.

satela [25.4K]

Answer:

$P(x\geq 7)=0.1886$

Step-by-step explanation:

The variable x, that said the number of customer that will order a nonalcoholic beverage in a sample of n customers follows a binomial distribution. Because we have n identical and independent events with a probability p of success and (1-p) of fail.

So, the probability that x customers will order a nonalcoholic beverage is:

$P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}$

Where n is the size of the sample and p is the probability that a customer order a nonalcoholic beverage, so replacing the values, we get:

$P(x)=\frac{10!}{x!(10-x)!}*0.51^{x}*(1-0.51)^{10-x}$

Now, the probability that at least 7 will order a nonalcoholic beverage is equal to:

$P(x\geq 7)=P(7)+P(8)+P(9)+P(10)$

Where:

$P(7)=\frac{10!}{7!(10-7)!}*0.51^{7}*(1-0.51)^{10-7}=0.1267\\P(8)=\frac{10!}{8!(10-8)!}*0.51^{8}*(1-0.51)^{10-8}=0.0494\\P(9)=\frac{10!}{9!(10-9)!}*0.51^{9}*(1-0.51)^{10-9}=0.0114\\P(10)=\frac{10!}{10!(10-10)!}*0.51^{10}*(1-0.51)^{10-10}=0.0011$

So, $P(x\geq 7)$ is equal to:

$P(x\geq 7)=0.1267+0.0494+0.0114+0.0011\\P(x\geq 7)=0.1886$

Finally, the probability that in a sample of 10 customers, at least 7 will order a nonalcoholic beverage is equal to 0.1886

5 0

3 years ago

What interest rate per annum is a fund paying its clients if the third to the last payment of a depositor became Php 1,040.40 fr

noname [10]

Answer: 1.3%

Step-by-step explanation:

To find rate of interest (r) per annum for a fund deposit by depositor .

Initial saving payment P= $1,000

Amount after three years A =$1,040.40

we know that

$A=P(1+\frac{r}{100} )^n\\\\\Rightarrow\ 1040=1000(1+\frac{r}{100} )^3\\\Rightarrow\ \frac{1040}{1000} =(1+\frac{r}{100} )^3\\\Rightarrow\ 1.040=(1+\frac{r}{100} )^3\\\text{by taking log on both sides we get,}\\log(1.040)=log((1+\frac{r}{100} )^3)\\\Rightarrow\ 0.039=3log(1+\frac{r}{100})\\\Rightarrow\ 0.013=log(1+\frac{r}{100})\\\Rightarrow\ e^0.013=1+\frac{r}{100}\\\Rightarrow\ 1.013=(1+\frac{r}{100})\\\Rightarrow\ 1.013-1=\frac{r}{100}$

r=0.013×100=1.3%

4 0

3 years ago