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3 years ago

a bacteria triples it’s original population in 25 hours (A=3A0). How big will it’s population be in 100 hours

Mathematics

1 answer:

Maru [420]3 years ago

7 0

Answer:

81 times the original size

Step-by-step explanation:

AA0ktA=3A0=?=?=25hours=A0ekt

Substitute the values in the formula.

3A0=A0ek⋅25

Solve for k. Divide each side by A0.

3A0A0=e25k

Take the natural log of each side.

ln3=lne25k

Use the power property.

ln3=25klne

Simplify.

ln3=25k

Divide each side by 25.

ln325=k

Approximate the answer.

k≈0.044

We use this rate of growth to predict the number of bacteria there will be in 100 hours.

AA0ktA=3A0=?=ln325=100hours=A0ekt

Substitute in the values.

A=A0eln325⋅100

Evaluate.

A=81A0

At this rate of growth, we can expect the population to be 81 times as large as the original population.

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3 years ago

The point (3,0) lies on the graph of P(x)=x^3-7x^2+15x-9. True or False

swat32

Answer:

True

Step-by-step explanation:

We can plug in and see.

If (3,0) is on the graph of P, then P(3) will evaluate to 0.

Let's try it:

P(3)=(3)^3-7(3)^2+15(3)-9

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3 years ago

Find the side length of X

7nadin3 [17]

Answer:

7√3

Step-by-step explanation:

We can use pythagoreans theorem to solve this

Since, we know one side, and the hypotenuse, we can solve for the other side.

Pythagoreans theorem: a²+b²=c²

Where a and b are two sides, and c is the hypotenuse (the side opposite of the right angle)

In this triangle, 7 is the side, and 14 is the hypotenuse.

I will plug in the values into pythagoreans theorem, and then simplify:

$a^{2}+b^{2} =c^{2} \\\\7^{2} +x^{2} =14^{2} \\\\49+x^{2} =196\\\\x^{2} =147\\\\x=\sqrt{147} \\\\x=\sqrt{49*3 }\\\\ x=\sqrt{7^{2} *3 }\\\\x=7\sqrt{3}$

So x = 7√3

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