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netineya [11]
3 years ago
7

While playing a game, you move back 5 spaces with the roll of the number cube. Your friend moves forward 3 spaces. Write each am

ount as an integer.
Mathematics
2 answers:
kifflom [539]3 years ago
8 0
You: +5
Your friend: -3

hope this helps!
be sure to give me a good rating
LuckyWell [14K]3 years ago
3 0

Answer:

The integers will be -5 ,3.

Step-by-step explanation:

While playing a game, you move back 5 spaces with the roll of the number cube.

As you are moving back, it will be a negative value. The integer here will be -5.

Your friend moves forward 3 spaces.

The friend is moving forward, it will be a positive value. The integer will be 3.

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What is the area of triangle ABC?
Stella [2.4K]

9514 1404 393

Answer:

  C.  36√3 square units

Step-by-step explanation:

Your knowledge of special triangles tells you that height CD is ...

  CD = 6√3

so the area is ...

  A = 1/2bh

  A = 1/2(12)(6√3) = 36√3 . . . . square units

_____

<em>Additional comment</em>

The 30°-60°-90° right triangle that is half an equilateral triangle has a short side equal to half the length of the long side. The Pythagorean theorem tells you that the middle-length side is √(2²-1²) = √3 times the shortest side. That is, the side length ratios in this "special" triangle are ...

  1 : √3 : 2

This means the length DB is 12/2 = 6, and the length CD is 6√3.

7 0
3 years ago
Find the exact value of cos(theta) for an angle (theta) with tan (theta)= -2/3 and with its terminal side in Quadrant II.
Naya [18.7K]

Answer:

-\frac{3\sqrt{13}}{13}.

Step-by-step explanation:

Since we are in quadrant two, cosine value is negative while sine value is positive.

We are going to use the Pythagorean Identity: 1+\tan^2(\theta)=\sec^2(\theta).

1+(\frac{-2}{3})^2=\sec^2(\theta)

1+\frac{4}{9}=\sec^2(\theta)

\frac{9+4}{9}=\sec^2(\theta)

\frac{13}{9}=\sec^2(\theta)

\pm \sqrt{\frac{13}{9}}=\sec(\theta)

\pm \frac{\sqrt{13}}{3}=\sec(\theta)

Since cosine and secant are reciprocals then they will have the same sign as along as they both exist.

\sec(\theta)=-\frac{\sqrt{13}}{3}

\cos(\theta)=-\frac{3}{\sqrt{13}}.

I don't see this answer as I'm going to rationalize the denominator.

\cos(\theta)=-\frac{3}{\sqrt{13}} \cdot \frac{\sqrt{13}}{\sqrt{13}}.

\cos(\theta)=-\frac{3\sqrt{13}}{13}.

8 0
4 years ago
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Kobotan [32]

Answer: disregard my previous answer, it was incorrect, looking for right one right now

(you can delete this if you want)

6 0
3 years ago
???????????????????????????????????????????????
allochka39001 [22]
So it would be 4x+108= 180 because it’s a straight line so x=18. For the second one id say A and D
4 0
3 years ago
Read 2 more answers
A) x+(3x÷2y)<br>b) (b⁹)²×b⁵÷b¹¹=<br>c) (4²)⁶×4⁷÷4¹⁶=​
monitta

Answer:

a) x+3x/2y or (3x+2xy)/2y

b) b^12

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Step-by-step explanation:

4 0
3 years ago
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