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3 years ago

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William had $45 dollars to spend on Vegetables. After buying 6 watermelons , he had $25.50 left .how much did each watermelons c

ost ?

1 answer:

notka56 [123]3 years ago

5 0

Easy, just do 45-25.50= 19.50 and then divide 19.50 by 6, and then you get 3.25. So, your answer would be $3.25.

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In the figure below, j || h. Find the values of x and y.

SVEN [57.7K]

Answer:

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x=180°-81°

x=99°

x°=(3y+33)°

99°=(3y+33)°

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2 years ago

A researcher records the odometer reading and age of used Hondas. What kind of correlation is likely to be obtained for these tw

tresset_1 [31]

Using the concept of correlation, it is found that a strong positive correlation is expected between these two variables.

When two variables are direct proportional, that is, both increase together, there is a <em>strong positive correlation.</em>

In this problem, <u>the older the car</u>, the more it should have traveled, that is, the <u>higher the read on the odometer</u>, hence, there is a <em>direct proportional</em> relationship, which means that the variables have a strong positive correlation.

A similar problem is given at brainly.com/question/15468813

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2 years ago

N+9/4n+36 simplify this

scoundrel [369]

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3 years ago

Read 2 more answers

5/6 x 12 in simplest form?

Jlenok [28]

Answer:

10

Step-by-step explanation:

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3 years ago

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Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y

I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

$\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }$

$\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }$

$\mathbf{ YX = \sqrt{(3)^2+(6)^2} }$

$\mathbf{ YX = \sqrt{9+36} }$

$\mathbf{ YX = \sqrt{45} }$

$\mathbf{ YX = \sqrt{9*5} }$

$\mathbf{ YX = 3 \sqrt{5} }$

Thus; the exact length of the midsegment of trapezoid JKLM = $\mathbf{ = 3 \sqrt{5} }$ i.e 6.708 units on the graph

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2 years ago