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yKpoI14uk [10]
3 years ago
14

Finding the discriminant

Mathematics
1 answer:
mario62 [17]3 years ago
7 0
I believe the answer you are looking for is 16
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100 POINTS <br> Evaluate the derivative of the function number 38
patriot [66]

Answer:

 1/ sqrt(1+ln^2(x))    * 1/(ln^2x +1) * 1/x

Step-by-step explanation:

f(x) = sin (tan^-1 (ln(x)))  

u substitution

       d/du (sin u)  * du /dx

            cos (u) * du/dx

Let u =(tan^-1 (ln(x)))     du/dx =d/dx  (tan^-1 (ln(x)))

v substitution

                                             Let v = ln x                dv/dx = 1/x

                                              d/dv  (tan ^-1 v)  dv/dx

                                                          1/( v^2+1) * dv/dx

                                                        =1/(ln^2x +1) * 1/x

Substituting this back in for  du/dx

cos (tan^-1 (ln(x))  * 1/(ln^2x +1) * 1/x

We know that cos (tan^-1 (a)) = 1/ sqrt(1+a^2)

cos (tan^-1 (ln(x))  * 1/(ln^2x +1) * 1/x

 1/ sqrt(1+ln^2(x))     * 1/(ln^2x +1) * 1/x

                                           

8 0
3 years ago
Read 2 more answers
What is the equation of the line through (2,1) and (0, 5)
aivan3 [116]

Answer:

y=-2x+5

Step-by-step explanation:

Trust me please

5 0
2 years ago
Of the 6 people attending a seminar, 3 have red hair.
marin [14]

Answer:

1/2

Step-by-step explanation:

Total -- 6 people

3 people -- 3/6 = 1/2

Therefore, the answer is 1/2

3 0
3 years ago
A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n&#10;\\&#10;\\=\frac{t_1}{5}(5)^n

Comparing this to our general form, we see that
\frac{t_1}{5}=75

Multiplying by 5 on both sides, we get that
t₁ = 75*5 = 375

The recursive formula for a geometric sequence is given by
t_n=t_{n-1}(r), while we must state what t₁ is; this gives us

t_1=375; t_n=t_{n-1}(5)

3 0
3 years ago
Helpppp for those who can read bahasa pleaseee
wlad13 [49]

Answer:

me

Step-by-step explanation:

7 0
3 years ago
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