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Margarita [4]
3 years ago
7

From the 12 male and 8 female sales representatives for an insurance​ company, a team of 4 men and 4 women will be selected to a

ttend a national conference on insurance fraud.
Requried:
In how many ways can the team of 6 representatives be selected?
Mathematics
1 answer:
Flura [38]3 years ago
4 0

Answer:

Total ways = ¹²C₄ × ⁸C₄

Total ways = 495 × 70

Total ways = 34,650

Therefore, there are 34,650 ways to select a team of 4 men and 4 women from 12 male and 8 female sale representatives.

Step-by-step explanation:

From the given information,

There are 12 male sales representatives

There are 8 female sales representatives

We want to select a team of 4 men and 4 women

Requried:

In how many ways can the team of 6 representatives be selected?

There must be a typing error since it is given in the question that 4 men and 4 women are to be selected.

4 + 4 = 8

So the correct question is

In how many ways can the team of 8 representatives be selected?

A team of 4 men from 12 men may be selected as

Men = ¹²C₄ = 495 ways

A team of 4 women from 8 women may be selected as

Women = ⁸C₄ = 70 ways

So the team of 8 representatives may be selected as

Total ways = ¹²C₄ × ⁸C₄

Total ways = 495 × 70

Total ways = 34,650

Therefore, there are 34,650 ways to select a team of 4 men and 4 women from 12 male and 8 female sale representatives.

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Triss [41]

Answer:

684

Step-by-step explanation:

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SOMEONE HELP PLEASE !!! <br><br> n^2 - m; use m = 7, and n = 8
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

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Step-by-step explanation:

<u>Step 1: Define</u>

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<u>Step 2: Evaluate</u>

  1. Substitute:                    8² - 7
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Step-by-step explanation:

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Evgen [1.6K]

Answer:

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Step-by-step explanation:

Let

x------> the number of years

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Solve for x

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