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elena-s [515]
2 years ago
8

Type a digit that makes this statement true.

Mathematics
2 answers:
oksian1 [2.3K]2 years ago
7 0

Answer:

Answer:

1, 3, 5, 7, or 9

Step-by-step explanation:

For 14, 213, 1__2 to be divisible by 4, the last two digits must be divisible by 4.

Using this knowledge, any odd single digit number would make the statement true.

14, 213, 112 ÷ 4 = 3, 553, 278

14, 213, 132 ÷ 4 = 3, 553, 283

14, 213, 152 ÷ 4 = 3, 553, 288

14, 213, 172 ÷ 4 = 3, 553, 293

14, 213, 192 ÷ 4 = 3, 553, 298

Step-by-step explanation:

Aneli [31]2 years ago
3 0

Answer:

1, 3, 5, 7, or 9

Step-by-step explanation:

For 14, 213, 1__2 to be divisible by 4, the last two digits must be divisible by 4.

Using this knowledge, any odd single digit number would make the statement true.

14, 213, 112 ÷ 4 = 3, 553, 278

14, 213, 132 ÷ 4 = 3, 553, 283

14, 213, 152 ÷ 4 = 3, 553, 288

14, 213, 172 ÷ 4 = 3, 553, 293

14, 213, 192 ÷ 4 = 3, 553, 298

Hope this helped!

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7 0
3 years ago
What is the simplified form of the expression?
zimovet [89]

Answer:

7c^2d-7c+4d-10

Step-by-step explanation:

Start off with the term that has c^2 in it. 5c^2d + 2C = 7c^2d, then since you have multiple choice, the d value differs between the two answer choices that have 7c^2d so you can do +3d +d to get +4d to get the fourth answer choice.

To check your work, you can add/subtract each term to see if you get 7c^2d-7c+4d-10

3 0
3 years ago
A cell site is a site where electronic communications equipment is placed in a cellular network for the use of mobile phones. Th
Olegator [25]

Answer:

(a) 74553

(b) 172120

(c) 234802

Step-by-step explanation:

Given

y = \frac{340110}{1 + 377e^{-0.259t}}

Solving (a): 1998

Year 1998 means that:

t =1998 -  1980

t =18

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*18}}

y = \frac{340110}{1 + 377e^{-4.662}}

y = \frac{340110}{1 + 3.562}

y = \frac{340110}{4.562}

y = 74553 --- approximated

Solving (b): 2003

Year 2003 means that:

t = 2003 -  1980

t =23

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*23}}

y = \frac{340110}{1 + 377e^{-5.957}}

y = \frac{340110}{1 + 0.976}

y = \frac{340110}{1.976}

y = 172120 --- approximated

Solving (c): 2006

Year 2006 means that:

t = 2006 -  1980

t =26

So, we have:

y = \frac{340110}{1 + 377e^{-0.259*26}}

y = \frac{340110}{1 + 377e^{-6.734}}

y = \frac{340110}{1 + 0.4485}

y = \frac{340110}{1.4485}

y = 234802 --- approximated

3 0
2 years ago
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