All categories

2 years ago

Type a digit that makes this statement true.

Mathematics

2 answers:

oksian1 [2.3K]2 years ago

7 0

Answer:

Answer:

1, 3, 5, 7, or 9

Step-by-step explanation:

For 14, 213, 1__2 to be divisible by 4, the last two digits must be divisible by 4.

Using this knowledge, any odd single digit number would make the statement true.

14, 213, 112 ÷ 4 = 3, 553, 278

14, 213, 132 ÷ 4 = 3, 553, 283

14, 213, 152 ÷ 4 = 3, 553, 288

14, 213, 172 ÷ 4 = 3, 553, 293

14, 213, 192 ÷ 4 = 3, 553, 298

Step-by-step explanation:

Aneli [31]2 years ago

3 0

Answer:

1, 3, 5, 7, or 9

Step-by-step explanation:

For 14, 213, 1__2 to be divisible by 4, the last two digits must be divisible by 4.

Using this knowledge, any odd single digit number would make the statement true.

14, 213, 112 ÷ 4 = 3, 553, 278

14, 213, 132 ÷ 4 = 3, 553, 283

14, 213, 152 ÷ 4 = 3, 553, 288

14, 213, 172 ÷ 4 = 3, 553, 293

14, 213, 192 ÷ 4 = 3, 553, 298

Hope this helped!

You might be interested in

The Harper family drove 510 miles on their vacation. Mr. Harper and Mrs. Harper took turns driving. Mr. Harper drove 4 times as

Korvikt [17]

Mrs. Harper drove 102 miles and Mr. Harper drove 408. Am I right?

6 0

3 years ago

Read 2 more answers

Help!! Lots of points

murzikaleks [220]

$\frac{ {5}^{2} }{ {2}^{2} } = {( \frac{5}{2}) }^{2}$
Since they are both squared.

Evaluating 5^2 and 2^2 and finding the quotient also works.

$\frac{ {5}^{2} }{ {2}^{2} } = \frac{5 \times 5}{2 \times 2} = \frac{25}{4} = 6.25\\ \frac{ {5}^{2} }{ {2}^{2} } = {( \frac{5}{2} )}^{2} = 2.5 \times 2.5 = 6.25$
The third option, "Evaluate 5^2 and 2^2 ...," and the last option, "Rewrite the expression as (5/2)^2 ...," are the correct choices.

3 0

3 years ago

Read 2 more answers

Find the equation of the line through the points (−2,5) and (4,9).

3241004551 [841]

9514 1404 393

Answer:

2x -3y = -19

Step-by-step explanation:

Taking the differences between the given points, we have ...

(Δx, Δy) = (4, 9) -(-2, 5) = (6, 4)

The equation of the line can be written ...

Δy·x -Δx·y = Δy·(x1) -Δx·(y1) . . . . . for point (x1, y1) on the line

4x -6y = 4(-2) -6(5) = -38

Dividing by 2 gives the standard form equation ...

2x -3y = -19

_____

<em>Additional comment</em>

The original equation 4x-6y=-38 satisfies the requirements of this problem. However, "standard form" requires the numbers in the equation be mutually prime (in addition to the problem requirements). That is, they must have no common factors. Hence, we must remove the common factor of 2 in order to have true "standard form."