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pickupchik [31]
3 years ago
9

Geometry and I need help

Mathematics
2 answers:
Helga [31]3 years ago
5 0
Y=11 is what i got not sure if it’s right
Yanka [14]3 years ago
3 0

Answer:

y = 11

Step-by-step explanation:

We use the definition of Supplementary Angles and Adjacent Angles.

Step 1: Set up equation 1 (Definition of Supplementary Angles)

5x - 4 +7x - 8 = 180

Step 2: Solve for <em>x</em>

12x - 4 - 8 = 180

12x - 12 = 180

12x = 192

x = 16

Step 3: Plug in <em>x</em>

5(16) - 4

80 - 4

76°

Step 4: Set up equation 2 (Definition of Supplementary Angles)

76 + 9y + 5 = 180

Step 5: Solve for <em>y</em>

9y + 81 = 180

9y = 99

y = 11

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Goryan [66]

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Step-by-step explanation:

3 0
3 years ago
If Anna have 8000 and gave jim 300 and bought some items a shoes for 290 a suit for 400 and a phone for 2000
vovangra [49]

Answer: Assuming the unit is dollars, the answer would be $5,010.

Explanation:

Step 1: 8000-300 is 7700.

Step 2: 7700-290 is 7410

Step 3: 7410-400 is 7010

Step 4: 7010-2000 is 5010

So, the answer is Anna has $5,010 dollars left after giving Jim $300, buying shoes for $290, a suit for $400 and spending $2,000 dollars on a new phone.

6 0
3 years ago
A continuous random variable X has cdf F(x)=x² b (a) Determine the constants a and b. for a &lt; 0, for 0 &lt; x &lt; 1, for x &
Karolina [17]

Any proper CDF F(x) has the properties

• \displaystyle \lim_{x\to-\infty} F(x) = 0

• \displaystyle \lim_{x\to+\infty} F(x) = 1

so we have to have a = 0 and b = 1.

This follows from the definitions of PDFs and CDFs. The PDF must satisfy

\displaystyle \int_{-\infty}^\infty f(x) \, dx = 1

and so

\displaystyle \lim_{x\to-\infty} F(x) = \int_{-\infty}^{-\infty} f(t) \, dt = 0 \implies a = 0

\displaystyle \lim_{x\to+\infty} F(x) = \int_{-\infty}^\infty f(t) \, dt = 1 \implies b = 1

8 0
2 years ago
What is 1.7¯ expressed as a fraction in simplest form?
tatiyna

16/9.................

5 0
3 years ago
-6y^2 + 9y^2 - y - 9 - 7y^2 + 1 + 10y + 3y
taurus [48]

Answer: -4y^(2)+12y-8

Step-by-step explanation: Combine like terms

6 0
3 years ago
Read 2 more answers
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