3 pieces of wood have a total length of 32 m. The second piece is twice the size of the first and the third piece is 2 more mete
rs than triple the first. What are the lengths of the pieces of wood? Please explain througly (problem solving algebraically)
1 answer:
Answer:
X + Y + Z = 32
X2 = Y
X3 + 2 = Z
X + X2 + X3 + 2 = 32
Make X alone
There is a 2 so we subtract 2 from both sides
X + X2 + X3 = 30
Add the X's up
X + X2 + X3 = X6
X6 = 30
Divide by 6
30 / 6 = 5
You are left with X=5
The first piece of wood has a length of 5
5 x 2 = 10
The second piece has a value of 10
5 x 3 + 2 = 17
The third piece is 17
Hope this helps. If you have any questions you may ask.
Step-by-step explanation:
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