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galben [10]
3 years ago
15

3 pieces of wood have a total length of 32 m. The second piece is twice the size of the first and the third piece is 2 more mete

rs than triple the first. What are the lengths of the pieces of wood? Please explain througly (problem solving algebraically)
Mathematics
1 answer:
andreev551 [17]3 years ago
5 0

Answer:

X + Y + Z = 32

X2 = Y

X3 + 2 = Z

X + X2 + X3 + 2 = 32

Make X alone

There is a 2 so we subtract 2 from both sides

X + X2 + X3 = 30

Add the X's up

X + X2 + X3 = X6

X6 = 30

Divide by 6

30 / 6 = 5

You are left with X=5

The first piece of wood has a length of 5

5 x 2 = 10

The second piece has a value of 10

5 x 3 + 2 = 17

The third piece is 17

Hope this helps. If you have any questions you may ask.

Step-by-step explanation:

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The true statement regarding the intervals where the function is increasing and decreasing is option A: The function is increasing from (–∞, 0).

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A function is defined as a relation between the set of inputs having exactly one output each.

On a coordinate plane, a parabola opens down with solid circles along the parabola at (-3, -5), (-2, 0), (-1, 3), (0, 4), (1, 3), (2, 0), (3, -5).

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The range is all real numbers.

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x=\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}&#10;\\ \\N=\frac{-(-2)+/-\sqrt{(-2)^{2} -4*1*(-M)} }{2*1}&#10;\\ \\ N=\frac{2+/-\sqrt{4+4M} }{2} \\ \\ N=\frac{-2+/-2\sqrt{1+M} }{2} = -1+/-\sqrt{1+M} \\ \\ N = -1 +\sqrt{1+M} \ or\ N=-1-\sqrt{1+M}


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